The hexadecimal eqquivalent of (80)10 is
1 answer:
You might be interested in
Answer:
Explanation:
Since the array is not provided, I created a Python function that takes in the array and loops through it counting all of the words that are longer than 5. Then it returns the variable longer_than_five. To test this function I created an array of words based on the synapse of Pride and Prejudice. The output can be seen in the attached picture below.
def countWords(p_and_p_words):
longer_than_five = 0
for word in p_and_p_words:
if len(word) > 5:
longer_than_five += 1
return longer_than_five
