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Paha777 [63]
3 years ago
8

Where can the Ease of Access and Speech Recognition centers be found?

Computers and Technology
2 answers:
VashaNatasha [74]3 years ago
5 0
1. Choose Start, Control Panel.
In the Control Panel, choose Ease of Access.
2. In the Ease of Access Center, choose Set up microphone under Speech Recognition.
3. Select the type of microphone you plan to use with Speech Recognition, then choose Next.
4. Choose Next again. You should see a screen where you can check the microphoneʼs input level by reading some text. When youʼre done checking the levels, choose Next, then Finish.
5. Choose Speech Recognition, then “Train your computer to better understand you.”
6. You will read a series of screens to train the Speech Recognition feature. This process should take about 5-10 minutes.
7. When youʼre finished, choose Next, then Donʼt Send.
Taking the time to train the Speech Recognition feature will improve how well this feature will work with your voice and is highly recommended.

(Sorry for so many steps
but I hope this helps!!)
Bess [88]3 years ago
3 0

Answer:

bottom right

Explanation:

at least on windows it's bottom right

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The do-while loop for the given problem is shown below.  

do  

{  

  // user asked to enter two numbers  

  cout<<"Enter two numbers to be added."<<endl;  

  cin>>num1;  

  cin>>num2;  

  sum = num1 + num2;  

 

  // sum of the numbers is displayed  

  cout<<"Sum of the two numbers is "<<sum<<endl;  

  // user asked whether to perform the operation again  

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The variables to hold the two numbers and their sum are declared as float so that the program should work well for both integers and floating numbers.

float num1, num2, sum;

The char variable is taken since it holds only a single-character input from the user, 'y' or 'n'.

char choice;

The whole program is given below.

#include <iostream>

using namespace std;

int main() {

float num1, num2, sum;

char choice;  

do  

{  

  // user asked to enter two numbers  

  cout<<"Enter two numbers to be added."<<endl;  

  cin>>num1;  

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  cin>>choice;  

}while(choice != 'n');

cout<<"Quitting..."<<endl;

}

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