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AleksAgata [21]
3 years ago
10

Here is a list of numbers:

Mathematics
2 answers:
Eva8 [605]3 years ago
7 0

Answer:

-7.5

Step-by-step explanation:

The median is all the numbers put in order, then the middle number

Here is what that looks like:

2, -1, 11, -18, -4, 13, -11, -17, -17, -17

                        \/

-18, -17, -17, -17, -11, -4, -1, 2, 11, 13

                        \/

-18, -17, -17, -17, -11, -4, -1, 2, 11, 13

                        \/

-18, -17, -17, -17, -11, -4, -1, 2, 11, 13

                        \/

-18, -17, -17, -17, -11, -4, -1, 2, 11, 13

                        \/

Since we have two numbers in the middle

we add them together and divide by 2

                        \/

-11 + -4 = -15 / 2 = -7.5

ehidna [41]3 years ago
3 0

Answer:

put the numbers in order from least to greatest and then cross them out til you get to the center number

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A baseball team won 2 games. They played 17 games total. Which ratio shows how many games they lost
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Answer:

15/17

Step-by-step explanation:

if they won 2 games they lost 15 (17-2)  so the ratio is 15/17

6 0
3 years ago
What are the coordinates of the vertices of the pre-image given? ry= −x ◦ T1, −2(x, y) 
nataly862011 [7]
<h3><u>Answer:</u></h3>

Hence, the coordinates of pre-image are:

A(1,6) , B(0,4) , C(3,4) , D(2,6)

<h3><u>Step-by-step explanation:</u></h3>

We have to find the  coordinates of the vertices of the pre-image given?

Ry= −x ◦ T_1, −2(x, y)

i.e. we have to find the composition of reflection along the line y=-x and translation with the rule:

(x,y) → (x+1,y-2)

Now we have coordinates of A",B",C" and D" as:

A"(-4,-2)

B"(-2,-1)

C"(-2,-4)

D"(-4,-3)

Now we are asked to find the coordinates of the pre-image.

Also when any point is reflected along y=-x then the point is transformed to:

(x,y) → (-y,-x)

Let A,B,C and D are the points of the pre-image.

Hence, the coordinates of the pre-image are given as:

so, the transformation is given as:

A→A'→A"

B→B'→B"

C→C'→C"

D→D'→D"

Where A',B',C',D' represents the transformation after translation and A",B",C",D" represents the transformation after reflection as well.

The coordinates of A' are (2,4)

B' are (1,2)

C' are (4,2)

and D' are (3,4)

Now, the coordinates of pre-image are given as:

A'(x,y)  → A(x-1,y+2)=A(1,6)

B'(x,y)  → B(x-1,y+2)=B(0,4)

C'(x,y)  → C(x-1,y+2)=C(3,4)

and D'(x,y)  → D(x-1,y+2)=D(2,6)

Hence, the coordinates of pre-image are:

A(1,6) , B(0,4) , C(3,4) , D(2,6)

4 0
3 years ago
M plain candies come in various colors. According to the MM/Mars Department of Consumer Affairs, the distribution of colors for
ioda
Given that the distribution of colors for plain MM andies is as follows:

<span>Colors      -      Purple   Yellow   Red   Orange   Green   Blue   Brown
Percentage -     20%      20%    20%     10%       10%    10%    10%

Suppose one candy is taken at random from a large bag of plain MM candies, the probability that the candy is purple of orange is given by:

P(purple candy or orange candy) = P(purple candy) + P(orange candy) = 20% + 10% = 30%
</span>
4 0
4 years ago
The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi
Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Now, z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

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