All categories

3 years ago

Simplify. √ 343 mlsldkdkdkdkdkddkd

Mathematics

2 answers:

Diano4ka-milaya [45]3 years ago

6 0

The square root of 343 is 18.520 or 18.52 or also 18

lorasvet [3.4K]3 years ago

6 0

Answer:

7√

Step-by-step explanation:

We will have to divide this radical equation into two, which at this case, would be: √49 • √7.

Afterward, we will be able to simplify √49 which would be 7 but √7 would remain the same since we can't simplify it.

In conclusion, the final answer would be 7√7. (18.520259)

You might be interested in

If points of a region represent equally-likely outcomes, then you can find probabilities by comparing areas.... T/F?

Anarel [89]

<span>If points of a region represent equally-likely outcomes, then you can find probabilities by comparing areas would be true.</span>

3 0

3 years ago

A cable company charges $70 per month for cable service. Please help ASAP Check screenshot pleasee (20 points) Thank youu! :)) &

LiRa [457]

Answer:

for #1: 70x = y

for #2: 70x + 100 = y

Step-by-step explanation:

you pay $70 for x amount of time with will equal your total therefore it's 70x = y

if you have to pay a one-time fee of $100.00 then you have to add that to your equation giving you 70x + 100 = y

hope this is right

hope it helps too :)

8 0

3 years ago

Pleaseeeee help I’m begging someone I PROMISE. I will mark brainlest

Lerok [7]

Answer:

Step-by-step explanation:

a) x>0 → items can not be negative

b) c(2,000) = 5,000+1.3(2,000) = $7,600

c)5,000+1.3x<10,000

5,000-5,000+1.3x<10,000-5,000

1.3x<5,000

x<3846 items

5 0

3 years ago

Dividing monomials please help and quick!!

Snezhnost [94]

Answer:

answer is of left to right

16x^14/(36x^2)=4x^12/9

(3^3)×(x^5)×y÷4

-9a^3(b^5)

7 0

3 years ago

Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?

photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

$D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6$

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

$T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326$

What is the probability that they are both queens?

$P = \frac{D}{T} = \frac{6}{1326} = 0.0045$

0.45% probability that they are both queens.

4 0

3 years ago