Question:
Find the gradient of the line passing through (6,8) and (4,10).
Answer:
-1 is the right answer.
Step-by-step explanation:
Slope of the line = The gradient of the line
Gradient of the line is known as change in the value of y-axis by change in the value of x-axis
Gradient = ∆y\∆x

Answer:
5
Step-by-step explanation:
here, the highest degree is 5 so the degree of polynomial is also 5.
The original annual simple interest rate, rounded to two decimal places, is 3.79%
What is the formula for simple interest?
The simple interest on a loan or deposit is determined as the principal multiplied by the simple interest rate and time
I=PRT
The first loan:
P=12 850.00
R=r(assume it is r)
T=4 years
I=12 850.00*r*4
I=51400r
The second loan was taken after 14 quarters the first was taken out, which is the same as after 3.5 years, hence, the interest on the second loan is only for a half a year
P=3 273.00
R=0.5r( half of the interest on the first loan)
T=0.5 years
I=3 273.00*0.5r*0.5
I= 818.25r
Total interest=51400r+818.25r
Total interest=52218.25r
total interest paid=1 980.00
1 980.00=52218.25r
r=1 980.00/52218.25
r=3.79%
Find out more about simple interest on: brainly.com/question/1115815
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Two expressions for the perimeter of a square are:
4a
- a represents one side of the square
a + a + a + a
- a representa one side of the square
the first expression does not include any addition. But the two expressions are actually equivalent.
Answer:
Step-by-step explanation:
4x > -16 reduces to x > -4: All numbers greater than x = -4 (shaded area to the right of -4).
6x < -48 reduces to x < -8: All numbers to the left of -8 (shaded area to the left of -8).
Solution: (-infinity, -4) ∪ (-8, infinity)
The number line between -8 and -4 is not part of the solution set (is not shaded or darkened)
Draw an open circle at -8 and extend an arrow to the left of this circle. Then draw an open circle at -4 and extend an arrow to the right of this circle.