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victus00 [196]
3 years ago
7

Help answer pls!!!!!!!!!!!!!!!! yes

Mathematics
2 answers:
sasho [114]3 years ago
6 0

Answer: D!

Step-by-step explanation:

Marysya12 [62]3 years ago
6 0

Answer: D is the ans

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REPOST PLEASE HELP !!!!
Jlenok [28]

Answer:

-3*23

Step-by-step explanation:

6 0
2 years ago
Segments
Kazeer [188]

Given

AB  and  CD  intersect

AC,  CB,  BD  and  AD  are congruent.

Prove that AB  is the bisector of ∠CAD and ray  CD  is the bisector of ∠ACB.

and AB  and  CD  are perpendicular.

To proof

Bisector

<em>A bisector is that which cut an angle in two equal parts.</em>

In ΔACB and ΔADB

AD = AC  ( Given )

AB = AB   ( common )

BC = DB  ( Given )

by SSS congurence property

we have

ΔACB ≅ΔADB

∠CAB =∠ DAB

∠CBA = ∠DBA

( By corresponding sides of the congurent triangle )

Thus AB is the bisector of the ∠CAD.

InΔ DAC and ΔDBC

AD = DB (Given)

AC = CB  ( Given )

CD = CD (common)

By SSS congurence property

ΔDAC≅ Δ DBC

∠  ACD =∠ BCD

∠ADC =∠BDC

( By corresponding sides of the congurent triangle )

Therefore CD is the bisector of the CAD.

In ΔBOC andΔ BOD

BO = BO ( Common )

∠BCO = ∠BDO

( As prove above ΔACB ≅ΔADB

Thus ∠ACB = ∠ADB by corresponding sides of the congurent triangle , CD is a bisector

∠BCO = ∠BDO )

 CB = DB ( given )

by SAS congurence property

ΔBOC ≅ ΔBOD

∠BOC =∠ BOD

∠BOC +∠ BOD = 180 °( Linear pair )

2∠ BOC = 180°

∠BOC = 90°

∠BOC =∠ BOD = 90°

also

In ΔCOA and ΔAOD

AO = AO ( Common )

∠ACO =∠ ADO

(  As prove above ΔACB ≅ΔADB Thus ACB = ADB by corresponding sides of congurent triangle ,CD is a bisector

thus  ∠ACO = ∠ADO )

AC =AD ( given )

by SAS congurence property

Δ COA ≅ ΔAOD

∠AOC = ∠AOD

( By corresponding angle of corresponding sides )

∠AOC + ∠AOD = 180°

2∠ AOC = 180°   ( Linear pair )

∠AOC = 90°

∠AOC = ∠AOD = 90 °

Thus AB  and  CD  are perpendicular.

Hence proved









   


 



6 0
3 years ago
The two numbers between the square root of two
KatRina [158]

Answer:

1 and 1.5

Step-by-step explanation:

but im not sure

8 0
3 years ago
Read 2 more answers
P= $1,000, t= 6, r= 11%, compounded annually (k = 1)​
kobusy [5.1K]

Answer:  well if p= $1000 and t=6 and r-11 %  then 6k+11=1000 then 11- 1000 is 6k=989 divide 6/ 164.83 i think

Step-by-step explanation:

8 0
3 years ago
Find the square by multiplying the polynomial <br> (4c + 4)²
MatroZZZ [7]

Answer:

16c² + 32c + 16

Step-by-step explanation:

(4c+4)² =

(4c+4)(4c+4) =

16c² + 16c + 16c + 16 =

16c² + 32c + 16

I think this is the answer you are looking for.

Hope this helped and have a good day

7 0
2 years ago
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