Answer:
Type I error: Concluding that mean mileage is less than 32 miles per hour when actually it is greater than or equal to 32 miles per gallon.
Step-by-step explanation:
We are given the following in the question:
Hypothesis:
Mean mileage for the Carter Motor Company's new sedan
We can design the null hypothesis and alternate hypothesis as:
![H_{0}: \mu \geq 32\text{ miles per gallon}\\H_A: \mu < 32\text{ miles per gallon}](https://tex.z-dn.net/?f=H_%7B0%7D%3A%20%5Cmu%20%5Cgeq%2032%5Ctext%7B%20miles%20per%20gallon%7D%5C%5CH_A%3A%20%5Cmu%20%3C%2032%5Ctext%7B%20miles%20per%20gallon%7D)
Type I error:
- It is the false positive error.
- It is the error of rejection a true hypothesis.
Type II error:
- It is the false negative error.
- It is the non rejection of a false null hypothesis.
Thus, type I error for the given hypothesis is concluding that mean mileage is less than 32 miles per hour when actually it is greater than or equal to 32 miles per gallon.
Type II error would be concluding that mean mileage is greater than or equal to 32 miles per gallon when actually it is less than 32 miles per gallon.
In logic, a biconditional<span> is a compound </span>statement<span> formed by combining two conditionals under "and." Biconditionals are true when both </span>statements<span> (facts) have the exact same truth value.
It could help you transform the statement into biconditional form.
I hope my answer has come to your help. God bless you and have a nice day ahead!
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Answer:
1.4.5m/s^2
2.6.25m/s^2
3.15m/s^2
4.0.05m/s^2
Step-by-step explanation:
a=v-u
----
t
27-0
------ = 27/6
6
=4.5m/s^2
u=4.5m/s
v=24.5m/s
t=3.2s
(24.5-4.5)÷3.2
=20/3.2
=6.25m/s^2
v=80m/s
u=50m/s
t=2s
(80-50)÷2
15m/s^2
v=0.80m/s
u=0.50m/s
t=6s
(0.80-0.50)÷6
=0.05m/s^2
Answer:
porfavor en español pls para yo poder resolverlo