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3 years ago

6

A box filled with books weighs 11 1/2 kilograms. Assume 1 kilogram = 2.20 pounds. What is the best estimate of the weight of the

box in pounds? O 20 pounds O 25 pounds O 30 pounds O I don't know

1 answer:

Bad White [126]3 years ago

5 0

Answer:

25 pounds.

Step-by-step explanation:

1 kg = 2.2 pounds

11.5 kg = x pounds Cross Multiply

1 * x = 11.5 * 2.2

Since you are estimating the question, you don't use a calculator. So 11.5 * 2

23 pounds. 11.5 * 0.2 = 2.3 pounds

Total = 23 + 2.3 = 25.3

So the total is more than 25 but way less than 30

You can make the question a bit more formal by noticing what I did was related to the distributive property.

11.5 ( 2 + 0.2) Remove the brackets.

11.5 * 2 + 0.2*11.5 Which gives you exactly the same thing as above.

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At the end of each quarter, Patti deposits $500 into an account that pays 12% interest compounded quarterly. How much will Patti

SVEN [57.7K]

Answer:

a.$7,096

Step-by-step explanation:

total amount A = s(\frac{(1+\frac{r}{n}) ^{n*t}-1 }{\frac{r}{n} } )[/tex]

[this is the formula used when certain amount is added at regular intervals and if the interest is COMPOUNDED]

(here,

s=deposit added at the end of each quarter= $500

n= number of times interest is compounded per unit 't'=4

t=total time = 3 years

r=interest rate ( expressed in decimal or fraction not in %) = 12/100 = 0.12 )

A= 500(\frac{(1+\frac{0.12}{4}) ^{4*3}-1 }{\frac{0.12}{4} } )[/tex]

by solving further,

A $=500(\frac{(1.03) ^{12}-1 }{0.03} )\\\\=500(\frac{1.42576-1}{0.03} )\\\\=500(\frac{0.42576}{0.03}) \\=$7,096$

( [1.03]^12= 1.42576 ( approximately) { use calculator for exact values})

3 0

3 years ago

A person standing cloes to the edge on the top of a 200-foot building throws a baseball vertically upward. The quadratic functio

RoseWind [281]

Answer:

See below in bold.

Step-by-step explanation:

A). s(t)= -16t^2+64t+200

Converting to vertex form.

s(t) = -16 (t^2 - 4t) + 200

s(t) = -16 [(t - 2)^2 - 4] + 200

s(t) = -16(t - 2)^2 + 64 + 200

s(t) = -16(t - 2)^2 + 264

The maximum height is after 2 seconds and it is 264 feet.

B) The ball hits the ground when s(t) = 0 so we have:

-16t^2+64t+200 = 0

x [-64 +/- sqrt (64^2 - 4*-16*200) ] / -32

x = 6.06, -2.06

So the answer is 6.06 seconds.

6 0

3 years ago

The equation y = \large 1\frac{1}{2}x represents the number of cups of dried fruit, y, needed to make x pounds of granola. Deter

Natasha2012 [34]

Answer:

$(1\frac{1}{2},1)$ - False

$(4,6)$ - True

$(18,12)$ -- False

$(0,0)$ -- True

$(2\frac{1}{2},3\frac{3}{4})$ -- True

Step-by-step explanation:

The points are

$(1\frac{1}{2},1)$ , $(4,6)$ , $(18,12)$ , $(0,0)$ and $(2\frac{1}{2},3\frac{3}{4})$ ---- missing from the question

Given

$y = 1\frac{1}{2}x$

Required

Determine if each of the points would be on $y = 1\frac{1}{2}x$

To do this, we simply substitute the value of x and of each point in $y = 1\frac{1}{2}x$ .

(a) $(1\frac{1}{2},1)$

In this case;

$x = 1\frac{1}{2}$ and $y = 1$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 1\frac{1}{2}$

$y = \frac{3}{2} * \frac{3}{2}$

$y = \frac{9}{4}$

$y = 2\frac{1}{4}$

<em>The point </em> $(1\frac{1}{2},1)$ <em> won't be on the graph because the corresponding value of y for </em> $x = 1\frac{1}{2}$ <em> is </em> $y = 2\frac{1}{4}$ <em></em>

(b) $(4,6)$

In this case;

$x = 4$

$y = 6$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 4$

$y = \frac{3}{2} * 4$

$y = \frac{3* 4}{2}$

$y = \frac{12}{2}$

$y = 6$

<em>The point </em> $(4,6)$ <em> would be on the graph because the corresponding value of y for </em> $x = 4$ is $y = 6$

(c) $(18,12)$

In this case:

$x = 18;y = 12$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 18$

$y = \frac{3}{2} * 18$

$y = \frac{3* 18}{2}$

$y = \frac{54}{2}$

$y = 27$

<em>The point </em> $(18,12)$ <em> wouldn't be on the graph because the corresponding value of y for </em> $x = 18$ <em> is </em> $y = 12$ <em></em>

(d) $(0,0)$

In this case;

$x =0; y = 0$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 0$

$y = 0$

<em>The point </em> $(0,0)$ <em> would be on the graph because the corresponding value of y for </em> $x = 0$ is $y = 0$

(e) $(2\frac{1}{2},3\frac{3}{4})$

In this case:

$x = 2\frac{1}{2}$ ; $y = 3\frac{3}{4}$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 2\frac{1}{2}$

$y = \frac{3}{2} * \frac{5}{2}$

$y = \frac{15}{4}$

$y = 3\frac{3}{4}$

<em>The point </em> $(2\frac{1}{2},3\frac{3}{4})$ <em> would be on the graph because the corresponding value of y for </em> $x = 2\frac{1}{2}$ is $y = 3\frac{3}{4}$

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3 years ago

For what value of a is the equation an identity? a(2x + 3) = 9x + 15 + x

saul85 [17]

The answer to the question

4 0

3 years ago

Add or subtract. –29 + 40

ollegr [7]

Answer: well, technically you add but.... the answer is 11. Since it's a negative, one way to find the answer is to subtract 40 from 29, which is 11.

Step-by-step explanation:

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3 years ago

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