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Yuki888 [10]
3 years ago
15

If a randomly selected customer was satisfied with his/her meal, what is the probability that the customer ordered fish

Mathematics
1 answer:
vodka [1.7K]3 years ago
7 0

Answer:

87.5%

Step-by-step explanation:

Complete question  -

75% of the people who eat at Doug's Diner order fish and 90% of the people who order fish also order fries. Given that 80% of all people who eat at Doug's order fries, what is the probability that a randomly chosen customer orders fries without fish?

Solution

Given

People who order fish at the Doug's Diner  = 75%

Out of this 75%, 90% also order  fries which means that nearly 67.5% ordered fries with the fish.

Given that, 80% of people dining at Doug's Diner order fries

Then percentage or people who ordered only fires and no fish = 80% - 67.5% = 12.5%

The probability of customers who ordered fish = 100 - 12.5% = 87.5%

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Vilka [71]

Answer:

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2 years ago
a 2014 mustang originally costs $25000.00 and depreciates at a rate of 8% per year. What is the cost of the car after 7 years?
frutty [35]
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Given:

Original cost: $25,000

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Term: 7 years

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Answer:

The simplified expression is:

\frac{3^9y}{2\times \:81}=\frac{243y}{2}

Step-by-step explanation:

Given the expression

\frac{3^9\times \:y}{2\times 81}

solving the expression

\frac{3^9\times \:y}{2\times 81}=\frac{3^9y}{162}

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Therefore, the simplified expression is:

\frac{3^9y}{2\times \:81}=\frac{243y}{2}

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2 years ago
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