<h2>Hello!</h2>
The answer is: None of the options.
The correct answer is: 
<h2>Why?</h2>
The total surface area of the cone is equal to:

Calculations:
tex]BaseArea=\pi*r^{2}=\pi*7^{2}=153.94cm^{2}[/tex]

[
So,

Have a nice day!
<h3>
Therefore she can cut 8 feet long log.</h3>
Step-by-step explanation:
Given,
The lengths in feet of three pieces of timber are 48,72 and 40. The sawmill operator needs to cut the timber into logs of equal length with no waste.
The HCF of 48 , 72 and 40 is =8
Therefore she can cut 8 feet long log.
Answer:
i believe the answer would be y= -x-4
Step-by-step explanation:
a line that is perpendicular, will have and opposite reciprocal slope, so:
the slope of the line y=x-4 is 1, and the reciprocal of 1 is also 1.
now take the opposite of it, which is -1.
so the perpendicular line equation would be y=-x-4
i hope this helps :D
Answer:
This question is incomplete. What exactly are we doing to the equation
PS; You can answer in the comment section. I'd help out there
Answer:
See explanation
Step-by-step explanation:
The given expression is: 
Recall that 24=3*8

Recall again that:





We rewrite in radical form to obtain
![\implies (8*3)^{\frac{1}{3}}=2\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Cimplies%20%288%2A3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D2%5Csqrt%5B3%5D%7B3%7D)