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2 years ago

Please help I don’t understand

Mathematics

2 answers:

Sauron [17]2 years ago

7 0

Answer:

-1.96312>-2.2360

Step-by-step explanation:

first find - $\sqrt{5}\\$

which is -2.2360679775

now round it to match the lenth of the other problem

-1.96312...

-2.2360...

now remember that the bigger the negitive number, the smaller it really is,

-1.96312>-2.2360

Finger [1]2 years ago

6 0

Answer:

They are both irrational

Step-by-step explanation:

Notice the ellipsis in the first number. This means that there's no repetition in the decimals, and thus, cannot be written as a fraction. For the second number, this is also irrational because it can't be written as a fraction since the decimals don't repeat.

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Please help guys

yarga [219]

Answer:

Step-by-step explanation:

yes.

x/y is a rational number

because xxby y is irrational that why x/y is rational number

7 0

3 years ago

-4=g+1<br> A. g=-4<br> B. g=4<br> C. g=-5<br> D. g=-3

statuscvo [17]

C. g=-5 is the correct answer

6 0

3 years ago

Read 2 more answers

Amina posts three large letters the postage is the same for each letter she pays with a £20 note her change is £14.96 what is th

soldi70 [24.7K]

Answer:

The cost of posting one letter = £1.68

Step-by-step explanation:

Total amount Amina has = £20

Amina's change = £14.96

Total cost spent on posting the letters = £20 - £14.96 = £5.04

And we're told that she posts 3 letters in total, with the cost of posting each letter the same.

Cost of posting 3 letters = £5.04

Cost of posting only 1 letter = (£5.04/3) = £1.68

Hence, the cost of posting a letter = £1.68

Hope this Helps!!!

4 0

3 years ago

Read 2 more answers

Let S be the solid beneath z = 12xy^2 and above z = 0, over the rectangle [0, 1] × [0, 1]. Find the value of m > 1 so that th

jonny [76]

Answer:

The answer is $\sqrt{\frac{6}{5}}$

Step-by-step explanation:

To calculate the volumen of the solid we solve the next double integral:

$\int\limits^1_0\int\limits^1_0 {12xy^{2} } \, dxdy$

Solving:

$\int\limits^1_0 {12x} \, dx \int\limits^1_0 {y^{2} } \, dy$

$[6x^{2} ]{{1} \atop {0}} \right. * [\frac{y^{3}}{3}]{{1} \atop {0}} \right.$

Replacing the limits:

$6*\frac{1}{3} =2$

The plane y=mx divides this volume in two equal parts. So volume of one part is 1.

Since m > 1, hence mx ≤ y ≤ 1, 0 ≤ x ≤ $\frac{1}{m}$

Solving the double integral with these new limits we have:

$\int\limits^\frac{1}{m} _0\int\limits^{1}_{mx} {12xy^{2} } \, dxdy$

This part is a little bit tricky so let's solve the integral first for dy:

$\int\limits^\frac{1}{m}_0 [{12x \frac{y^{3}}{3}}]{{1} \atop {mx}} \right.\, dx =\int\limits^\frac{1}{m}_0 [{4x y^{3 }]{{1} \atop {mx}} \right.\, dx$

Replacing the limits:

$\int\limits^\frac{1}{m}_0 {4x(1-(mx)^{3} )\, dx =\int\limits^\frac{1}{m}_0 {4x-4x(m^{3} x^{3} )\, dx =\int\limits^\frac{1}{m}_0 ({4x-4m^{3} x^{4}) \, dx$

Solving now for dx:

$[{\frac{4x^{2}}{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right. = [{2x^{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right.$

Replacing the limits:

$\frac{2}{m^{2} }-\frac{4m^{3}\frac{1}{m^{5}}}{5} =\frac{2}{m^{2} }-\frac{4\frac{1}{m^{2}}}{5} \\ \frac{2}{m^{2} }-\frac{4}{5m^{2} }=\frac{10m^{2}-4m^{2} }{5m^{4}} \\ \frac{6m^{2} }{5m^{4}} =\frac{6}{5m^{2}}$

As I mentioned before, this volume is equal to 1, hence:

$\frac{6}{5m^{2}}=1\\m^{2} =\frac{6}{5} \\m=\sqrt{\frac{6}{5} }$

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3 years ago

Jarod bought 8 yards of ribbon. He needs 200 inches to use to make curtains. How many inches of ribbon does he have?

frosja888 [35]

288 inches is needed

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3 years ago