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3 years ago

Marking as brainliest a question plz answer

Mathematics

1 answer:

saveliy_v [14]3 years ago

7 0

Step-by-step explanation:

a) the perimeter of the shape is similar to the perimeter of the one full rectangle =

2×(12+9) = 2× 21 = 42 cm

b) the area of the shape =

(12×9) -(4×6) = 108 -24 = 84 cm²

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≤ is used instead of < because it states more than, not "equal or more than" (meaning 97 sharp is fine)

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(-22, -3) and (1, -3)?

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3 years ago

Find dy/dx if y =x^3+5x+2/x²-1

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<u>Differentiate using the Quotient Rule</u> –

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According to the given question, we have –

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Let's solve it!

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2) \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5) - ( x^3+5x+2) 2x}{(x^2-1)^2 }\\$

$\qquad$ $\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\$

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\$

$\qquad$ $\pink{\therefore \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}} = \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\$

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Read 2 more answers

Marking as brainliest a question plz answer​

Marking as brainliest a question plz answer