3 years ago

PLEASE HELP ASAP!!!

Mathematics

1 answer:

Bezzdna [24]3 years ago

8 0

Part A is 2 batches of

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mestny [16]

Answer:

$(x^2-3^2)(x+3)$

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Step-by-step explanation:

Given

$(x^2-9)(x+3)$

Required

Select 3 equivalent expressions

$(x^2-9)(x+3)$

Express 9 as 3^2

$(x^2-3^2)(x+3)$ --- This is one equivalent expression

Take $x^2 - 3^2$ as difference of two squares

$(x-3)(x+3)(x+3)$ -- This is another equivalent expression:

Solving further:

$(x-3)(x+3)(x+3)$ becomes

$(x-3)(x+3)^2$ -- This is another equivalent expression:

Hence, the equivalent expressions are:

$(x^2-3^2)(x+3)$

$(x-3)(x+3)(x+3)$

$(x-3)(x+3)^2$

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2 years ago