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Angelina_Jolie [31]
2 years ago
7

PLS SOMEON EHELP PLS IM BEGGING FOR HELP IM SCRAEIMG FOR HELP

Mathematics
1 answer:
ohaa [14]2 years ago
3 0
None of your answers are correct

all you have to do it look at what place the value underlined

for example, find value of 5 in 517,849

the 5 is in the 100 thousands place this means that the value is 500,000
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A square has an area of 289 sq cm. what is the length of one side
Elodia [21]
289 square root = 17
17*17=289
Say 17 was length and 17 was width. L*w=289
Also, all sides of the square are the same.
5 0
2 years ago
Whats the value of 4
pantera1 [17]

Answer:

Hence, the value of the digit 4 will be i.e. 40 or forty. Example 1: Work out the place value, face value and value of 6 in the number 56,523.22.

8 0
3 years ago
A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so
Debora [2.8K]

Let A(t) = amount of salt (in pounds) in the tank at time t (in minutes). Then A(0) = 11.

Salt flows in at a rate

\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}

and flows out at a rate

\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}

which I'll solve with the integrating factor method.

\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95

-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}

\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}

Integrate both sides. By the fundamental theorem of calculus,

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)

\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}

\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}

\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}

After 1 hour = 60 minutes, the tank will contain

A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131

pounds of salt.

7 0
1 year ago
Here is a picture of a cube, and the net of this cube.
makvit [3.9K]

Answer:

96 ft²

Step-by-step explanation:

in a cube all sides are congruent so you take one measurement and multiply it by the number of sides, so you do 16 × 6 equals 96.

4 0
3 years ago
Read 2 more answers
Michael took his science test today and got a 14/16. What grade did he receive in total A/B/C??
In-s [12.5K]
He received an 87.5
5 0
3 years ago
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