What ratio is equivalent to 9 6

Mathematics

1 answer:

elena-s [515]2 years ago

6 0

3:2

the greatest common factor amongst 9 and 6 is 3

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A square with sides of 3 squareroot 2 is inscribed in a circle. what is the area of one of the sectors formed by the radii to th

mrs_skeptik [129]

Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.

So now we have the base and height of one of the triangular sections.

The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.

You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.

4 0

3 years ago

Pleaseeeee helpppppp!!

Sergio [31]

Answer: The equation of the circle as specified is (x+5)² + (y -1)² = 25

Step-by-step explanation: Use the Pythagorean Theorem to calculate the length of the radius from the coordinates given for the triangle location: A(-1,4), B(-1,1) and C(-5,1)

subtract y-values of A & B 4-1=3 AB = 3

subtract x-values of B &C -5-(-1) =4 BC=4 3² + 4² = 9 + 16 = 25

√25 = 5 AC = 5 That is the radiuus of the circle.

The sides of the triangle are AB=3, BC=4, AC=5.

Use the equation for a circle:

( x - h )² + ( y - k )² = r², where ( h, k ) is the center and r is the radius.

Use the coordinates of C, (-5, 1) as h and k in the equation

Substituting those values, we have (x -[-5])² + (y -[1])² = 5²

Simplify: (x+5)² + (y -1)² = 25

A graph of the circle is attached. The radius is AC, between the center C (-5,1) and A( -1,4) on the circumference. (Sorry, I still need to learn how to create line segments!)