Answer:
yes, triangle DEF is similar to triangle DBC, BC corresponds to EF, and angle DCB corresponds to angle F.
Step-by-step explanation:
Part A: Angle D is congruent to angle D by the reflexive property. Since line BC is parallel to line EF then angle DCB = angle DFE by corresponding angles. Hence triangle DEF is similar to triangle DBS by the AA Similarity Postulate.
Part B: BC corresponds to EF because they are in the same order and the triangles listed DEF and DBC
Part C: Angle DCB corresponds to angle F since they are corresponding angles with the two given parallel lines BC and EF.
Answer:
-1
Step-by-step explanation:
Answer:
It is proved that ∆ R S U ≅ ∆ T U S
Step-by-step explanation:
Compare Δ R S U & Δ T U S
∠ R = ∠ T
Side S U is common in both triangle.
So in these two triangles one angle & one side are same, so Property of similarity of triangles is satisfied. so
∆ R S U ≅ ∆ T U S
Proved.
Answer:
B
Step-by-step explanation:
hope this helps with the work