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Nostrana [21]
3 years ago
6

The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units? (1 point)

No, the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y No, the rectangle cannot have x = 60 and y = 11 because x = 24 + 2y Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 48 Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 24
Mathematics
2 answers:
Art [367]3 years ago
8 0
A would be you answer I don't know to explain it though Plz place me as brainliest.
Norma-Jean [14]3 years ago
7 0
A i took the test it is correct
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Edward has a box of following Skittles: 5 red, 4 green, 6 orange, 3 purple, and 7 yellow. He wants to know what the probability
balu736 [363]

Answer:

Let's add the total skittles to get our outcome:

25 in total.

5(red skittles)/25(total skittles in all)

7(yellow skittles)/24(total skittles in all NOW since you took a red skittle)

So therefore your expression is:

5/25 x 7/24

4 0
2 years ago
1. A square ABCD has the vertices A(n, n), B(n, -n), C(-n, -n), and D(-n, n). Which vertex is in Quadrant III?
andrew-mc [135]

The four quadrants and the sign of coordinates is given as follows:

Quadrant I : (n, n ) both x and y positive.

Quadrant II : ( -n,n) = x negative and y positive.

Quadrant III : ( -n,-n) = both x and y negative.

Quadrant IV: (n, -n) = x positive and y negative.

So Based on the above concept , we can say that vertex C (-n,-n) has both x and y negative and so it lies in quadrant III.

Answer is Vertex C (-n,-n)

5 0
3 years ago
Read 2 more answers
A shipping box has the dimensions shown what is the volume of the box in cubic yards? 1-4 yard 1-4 yard 1-2 yard
andriy [413]

The required picture is attached below :

Answer:

1 /32 yard³

Step-by-step explanation:

The volume of box can be obtained using the relation :

V = length * width * height

Length = 1/4 yards

Width = 1/2 yards

Height = 1/4 yards

Hence,

Volume (V) = 1/4 yards * 1/2 yards * 1/4 yards

Volume (V) = (1/4 * 1/2 * 1/4)(yard³)

Volume (V) = 1 / 32 yard³

4 0
2 years ago
For <img src="https://tex.z-dn.net/?f=e%5E%7B-x%5E2%2F2%7D" id="TexFormula1" title="e^{-x^2/2}" alt="e^{-x^2/2}" align="absmiddl
nevsk [136]
I'm assuming you're talking about the indefinite integral

\displaystyle\int e^{-x^2/2}\,\mathrm dx

and that your question is whether the substitution u=\dfrac x{\sqrt2} would work. Well, let's check it out:

u=\dfrac x{\sqrt2}\implies\mathrm du=\dfrac{\mathrm dx}{\sqrt2}
\implies\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt2\int e^{-(\sqrt2\,u)^2/2}\,\mathrm du
=\displaystyle\sqrt2\int e^{-u^2}\,\mathrm du

which essentially brings us to back to where we started. (The substitution only served to remove the scale factor in the exponent.)

What if we tried u=\sqrt t next? Then \mathrm du=\dfrac{\mathrm dt}{2\sqrt t}, giving

=\displaystyle\frac1{\sqrt2}\int \frac{e^{-(\sqrt t)^2}}{\sqrt t}\,\mathrm dt=\frac1{\sqrt2}\int\frac{e^{-t}}{\sqrt t}\,\mathrm dt

Next you may be tempted to try to integrate this by parts, but that will get you nowhere.

So how to deal with this integral? The answer lies in what's called the "error function" defined as

\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt

By the fundamental theorem of calculus, taking the derivative of both sides yields

\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}

and so the antiderivative would be

\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt{\frac\pi2}\mathrm{erf}\left(\frac x{\sqrt2}\right)

The takeaway here is that a new function (i.e. not some combination of simpler functions like regular exponential, logarithmic, periodic, or polynomial functions) is needed to capture the antiderivative.
3 0
3 years ago
I need help ASAP Right answers only!!
madam [21]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The graph has a line with a slope of 1/2 beginning at the origin and extending as far as you like into the first quadrant.

8 0
2 years ago
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