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3 years ago

2x2= what is the answer to this question.

Mathematics

2 answers:

lora16 [44]3 years ago

6 0

Answer:

2x2=4

Solution:

This question is the type of question, where the 2x2 can basically also be a 2+2 and get the same answer. But, any ways, if we do 2x1, then, we get 2, and if we get 2x2, then we just have to do the double of two, which is four.

Final Answer:

2x2=4

Multiply 2 and 2 and get 4.

Thanks:

Thank you, please mark me the brainliest!

AfilCa [17]3 years ago

3 0

Answer:

I'm pretty sure it's 4.

Step-by-step explanation:

I could be wrong though, It's such a hard problem.

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A line had a slope of 2/3 and a y intercept at (0,14).What is the x intercept of the line?

pychu [463]

Answer:

y=2/3x+14

Step-by-step explanation:

The standard form of an equation in slope-intercept form is y=mx+b where m=slope and b=y-intercept.

Given a y-intercept of 14 and a slope of 2/3, we can plug into the variables and get the equation y=2/3x+14

The x-intercept would be when y=0, so plugging in y=0 to the equation gets us:

0=2/3x+14

-14=2/3x

21=x

So the x-intercept is 21

6 0

3 years ago

HEEEEEELP !

iogann1982 [59]

If you meant to write y=23x-4 then none of the lines are perpendicular.

I suspect you intended y=2/3x-4, then line D, y=-3/2x-4 is perpendicular.

For any line y=mx+b, you have to "invert" m to get a perpendicular line. Inverting in this case means: flip numerator and denominator and add a minus sign.

So 2/3 becomes -3/2, hence answer D.

The 'inverted' m is called the opposite reciprocal. That's your word of the day.

6 0

3 years ago

Prove the theorem (AB )^T= B^T. A^T

Lisa [10]

Answer:

$(AB)^T = B^T.A^T (Proved)$

Step-by-step explanation:

Given (AB )^T= B^T. A^T;

To prove this expression, we need to apply multiplication law, power law and division law of indices respectively, as shown below.

$(AB)^T = B^T.A^T\\\\Start, from \ Right \ hand \ side\\\\B^T.A^T = \frac{B^T.A^T}{A^T}.\frac{B^T.A^T}{B^T} (multiply \ through) \\\\ = \frac{A^{2T}.B^{2T}}{A^T.B^T} \\\\=\frac{(AB)^{2T}}{(AB)^T} \ \ (factor \ out \ the power)\\\\= (AB)^{2T-T} \ (apply \ division \ law \ of \ indices; \ \frac{x^a}{x^b} = x^{a-b})\\\\= (AB)^T \ (Proved)$

3 0

3 years ago

The segment with endpoints (0,8) and (−6,0) is dilated to a segment with endpoints (0, 6) and (−4.5,0). What is the scale factor

sergiy2304 [10]

I think it would be 4/3 because when you multiply 8 by 4/3 you get 6 and when you multiply-6 by 4/3 you get -4.5 so

4/3

5 0

3 years ago

Solve the following system of equations using substitution <br> x = 4 <br> 2x + 4y = 36

DiKsa [7]

Just plug in 4 for the x

2*4 +4y =36
8+4y =36
4y =36-8
4y=28
y= 28/4
y=7

7 0

2 years ago

Read 2 more answers