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3 years ago

2x2= what is the answer to this question.

Mathematics

2 answers:

lora16 [44]3 years ago

6 0

Answer:

2x2=4

Solution:

This question is the type of question, where the 2x2 can basically also be a 2+2 and get the same answer. But, any ways, if we do 2x1, then, we get 2, and if we get 2x2, then we just have to do the double of two, which is four.

Final Answer:

2x2=4

Multiply 2 and 2 and get 4.

Thanks:

Thank you, please mark me the brainliest!

AfilCa [17]3 years ago

3 0

Answer:

I'm pretty sure it's 4.

Step-by-step explanation:

I could be wrong though, It's such a hard problem.

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Step-by-step explanation:

<u>Trigonometric Identities</u>

$\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B$

<u>Trigonometric ratios</u>

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

$\cos(\angle ABC)=\dfrac{3}{5}$

$\sin(\angle ABC)=\dfrac{4}{5}$

Therefore, using the trig identities and ratios:

$\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}$

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2 years ago

Read 2 more answers