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3 years ago

Indify 5(2x-3)=8x+3 .........

Mathematics

1 answer:

vivado [14]3 years ago

6 0

Answer:

solution,

5(2x-3) = 8x +3

or, 10x -15 = 8x+3

or, 10x -8 x= 3+15

or, 2x = 18

or, x = 18/2

or, x = 9

.:. x = 9

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40-s=23 what’s the value of S

GREYUIT [131]

Answer:

Step-by-step explanation:

Subtract 40 from s

-s=-17

Divide the negative sign

Divide by -1

-17 divided by -1 =17

4 0

3 years ago

Read 2 more answers

Please answer this correctly

Rudiy27

Answer:

The left graph

Step-by-step explanation:

Well the first big difference you see is that the right graph has 5 pieces of data between 10-19 and the left only has one. We actually only have one piece of data between 10-19 so our answer is the left graph.

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3 years ago

In ΔFGH, the measure of ∠H=90°, GF = 53, HG = 28, and FH = 45. What ratio represents the sine of ∠G?

andrew11 [14]

we have been given that in ΔFGH, the measure of ∠H=90°, GF = 53, HG = 28, and FH = 45. We are asked to find the ratio that represents the sine of ∠G.

First of all, we will draw a right triangle using our given information.

We know that sine relates opposite side of right triangle with hypotenuse.

$\text{sin}=\frac{\text{Opposite}}{\text{hypotenuse}}$

We can see from the attachment that opposite side to angle G is FH and hypotenuse is GF.

$\text{sin}(\angle G)=\frac{FH}{GF}$

$\text{sin}(\angle G)=\frac{45}{53}$

Therefore, the ratio $\frac{45}{53}$ represents the sine of ∠G.

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4 years ago

Test the claim below about the mean of the differences for a population of paired data at the level of significance α Assume the

Evgen [1.6K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is F

$t = 1.17$

$t_ {\alpha , df} =t_ {0.10 , 8} = 1.86$

Since the test statistics is outside the rejection region , we fail to reject the null hypothesis ,There is no statistically significant evidence to reject the claim

Step-by-step explanation:

From the question we are told that

The claim is $\mu = 0$

Hence

The null hypothesis is $H_o : \mu = 0$

The alternative is $H_a : \mu \ne 0$

Generally the test statistics is mathematically represented as

$t = \frac{\= d - \mu_d }{ \frac{s_d}{ \sqrt{n} } }$

=> $t = \frac{3.5 -0 }{ \frac{8.94}{ \sqrt{9} } }$

=> $t = 1.17$

Generally the degree of freedom is mathematically represented as

$df = n- 1$

$df = 9 - 1$

$df = 8$

From the student t-distribution table the critical value of $\alpha$ at a degree of freedom of 8 is

$t_ {\alpha , df} =t_ {0.10 , 8} = 1.86$

Since the $t_ {\alpha , df}$ is outside the rejection region , we fail to reject the null hypothesis ,There is no sufficient evidence to reject the claim

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4 years ago

What is 2x+y=17 in liner equation in slope intercept form?

Salsk061 [2.6K]

Answer:

y= -2x +17

Step-by-step explanation:

y=mx+b

work the equation to leave the y alone

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4 years ago