Solve the system of linear equations by graphing.

rosijanka [135]

Im sorry wish i could help but the equation is a little confusing give me a few moments and i will figure out the answer okay?

3 0

3 years ago

Read 2 more answers

Question 4 Find x 32°

Tcecarenko [31]

Answer:

picture?

Step-by-step explanation:

5 0

4 years ago

240,000 written as 10th power

kirill115 [55]

The answer is 24 to the 4th power

3 0

3 years ago

What is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (–5, 1)? Check all that ap

Ann [662]

Answer:

2x + 5y = -5

Step-by-step explanation:

Since the new line is parallel to the given line 2x + 5y = 10, the equation of the new line has exactly the same form as does 2x + 5y = 10, except that the constant will be different.

Were we to solve this equation (in standard form) for y in slope-intercept form, we'd get:

5y = -2x + 10, or

-2x + 10

y = ----------------

5

or

y = (-2/5)x + 2

Writing out 2x + 5y = C, we substitute -5 for x and 1 for y, obtaining

2x + 5y = C => 2(-5) + 5(1) = -10 + 5 = -5. Therefore, C = -5 and the equation of the new line is

2x + 5y = -5

6 0

3 years ago

when a card is drawn from a standard deck of 52 cards, what is the probability of getting a. queen b.a red. c.a queen or a red c

Brut [27]

(a) Probability of getting a queen from a deck of 52 cards = $\frac{1}{13}$

(b) Probability of getting a red card from a deck of 52 cards = $\frac{1}{2}$

(c) Probability of getting a queen or a red card from a deck of 52 cards = $\frac{7}{13}$

Solution:

Given that card is drawn from a standard deck of 52 cards.

Need to determine probability of getting

(a) queen (b) red (c) a queen or a red card

$\text { Probability of an event }=\frac{\text { favorable number of events }}{\text { total number of events }}$

(a) Calculating probability of getting a queen from a deck of 52 cards

Favorable events are getting a queen of spade, heart , diamond or club.

Means number of favorable events = 4

Total events is all possible outcomes from 52 cards

So Total number of event = 52

$\Rightarrow \text { probability of getting a queen }=\frac{4}{52}=\frac{1}{13}$

(b) Calculating probability of getting a red card from a deck of 52 cards

Number of red cards are 13 cards of diamonds and 13 cards of heart = 13+13 =26

So number of favorable event = 26

Total number of event = 52

$\Rightarrow \text { probability of getting a red card }=\frac{26}{52}=\frac{1}{2}$

(c) Calculating probability of getting a queen or red card from a deck of 52 cards

Favorable events are 26 red cards + two queens of spade and club. Need to keep in mind that queens of heart and diamond is already considered in 26 red cards.

So number of favorable event = (26+2) = 28

Total number of event = 52

$\text { Probability of getting a queen or red card }=\frac{28}{52}=\frac{7}{13}$

Summarizing the result :

(a) Probability of getting a queen from a deck of 52 cards = $\frac{1}{13}$

(b) Probability of getting a red card from a deck of 52 cards = $\frac{1}{2}$

(c) Probability of getting a queen or a red card from a deck of 52 cards = $\frac{7}{13}$

7 0

4 years ago