Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
Likely if you harm the ribosomes the cell will die. Cells absolutely require ribosomes for normal functioning...they are constantly replacing proteins (including enzymes and the ribosomal proteins) to keep alive.
Answer:
Most commonly, people get or transmit HIV through sexual behaviors and needle or syringe use. Only certain body fluids—blood, semen , pre-seminal fluid, rectal fluids, vaginal fluids, and breast milk—from a person who has HIV can transmit HIV.
Explanation:
That person will exhibit <span>monosomy,</span>
Answer:
I will give you an explanation, and try to figure it out!!
Explanation:
Incomplete dominance can occur because neither of the two alleles is fully dominant over the other, or because the dominant allele does not fully dominate the recessive allele. This results in a phenotype that is different from both the dominant and recessive alleles, and appears to be a mixture of both.
