We need to define our outcomes and events.
Finding the probability<span> of each event occurring
separately, and then multiplying the probabilities is the step to <span>finding
the probability</span> of two
independent events that occur in
sequence.
</span>
<span>
To solve this problem, we take note of this:</span>
The roll of the two dice are denoted by the pair
(I, j) ∈ S={ (1, 1),(1, 2),..., (6,6) }
Each pair is an outcome. There are 36 pairs and each has
probability 1/36. The event “doubles” is { (1, 1),(2, 2)(6, 6) } has
probability p= 6/36 = 1/6. If we define ”doubles” as a successful roll, the
number of rolls N until we observe doubles is a geometric (p) random variable
and has expected value E[N] = 1/p = 6.
Answer:
20 + 2 units
Step-by-step explanation:
because the perimeter of ∆ ABC is the answer 20 + 2
Answer:
A
Step-by-step explanation:
you will get 3(x-1)×(x+1) you can get the 3 and x by itself then it would be x+3
SO SORRY I ANSWERED ON THE OTHER ONE! The answer is C. This line has a negative slope, and the ending number tells you the y-intercept.
Answer:
Price = 20, Amount = 14
Step-by-step explanation:
A = Amount of Mangoes
P = Price for 1 Mango
P = A + 6
280 = P * A
insert A+6 for P
280 = (A+6) * A
280 = 6A + A²
280=1*a^2+6*a | Vertausche beide Seiten der Gleichung.
1*a^2+6*a=280 | quadratische Ergänzung: ergänze auf beiden Seiten (3)^2
1*a^2+6*a+(3)^2=3^2+280 | Rechne 3 hoch 2 aus.
1*a^2+6*a+(3)^2=9+280 | addiere 9 und 280
1*a^2+6*a+(3)^2=9+280 | Fasse die rechte Seite mit Hilfe der binomischen Formel zusammen.
1*(1*a+(3))^2=289 | Auf beiden Seiten Quadratwurzel ziehen.
1*a+(3)=+-*289^0.5
1*a_1+(3)=289^0.5
1*a_1+3=289^0.5 | Ziehe die Wurzel aus 289
1*a_1+3=17 | -3
1*a_1=14
