Answer:
hope this helps you.........
Answer:
The probability that at lest one job will be missed in 57 second is
=0.819134
Step-by-step explanation:
Poisson distribution:
A discrete random variable X having the enumerable set {0,1,2,....} as the spectrum, is said to be Poisson distribution.
for x=0,1,2...
λ is the average per unit time
Given that, a job arrives at a web server with the probability 0.03.
Here λ=0.03, t=57 second.
The probability that at lest one job will be missed in 57 second is
=P(X≥1)
=1- P(X<1)
=1- P(X=0)


=0.819134
(4x2 + 2y)(3x+y^2)
= 12x^3 + 4x^2y^2 + 6xy + 2y^3
coefficient of xy is ----> 6
X-intercept => 2x = 6 => x = 3
x-intercept is 3.
y-intercept => 3/2y = 6 => y = 4
y-intercept is 4.
z-intercept => 3z = 6 => z = 2
z-intercept is 2.
They correspond to any real number.