Answer:
Step-by-step explanation:
<u>We know that:</u>
- Area of shaded region = Area of square - Area of circles
- Radius of circle = 3 in
- Area of circle = πr²
- Area of square = s²
<u>Solution:</u>
- Area of shaded region = Area of square - Area of circles
- => Area of shaded region = (12²) - 4(22/7 x 3 x 3)
- => Area of shaded region = (144) - 4(22/7 x 9)
- => Area of shaded region = (144) - 4(198/7)
- => Area of shaded region = 144 - 792/7
- => Area of shaded region = 144 x 7/7 - 792/7
- => Area of shaded region = 1008/7 - 792/7
- => Area of shaded region = 1008/7 - 792/7
- => Area of shaded region = 216/7 in²
Answer:
Option 2: 
Step-by-step explanation:
Given:
From the triangle shown below;
A triangle QRS with angle QRS = 90°, ∠QSR = 30°.
Side QR = 5, SQ = 10 and RS = 5√3
Now, we know from trigonometric ratio that,
Here, opposite side of angle QSR is QR and Hypotenuse is the side opposite angle QRS which is SQ. Therefore,
Therefore, the value of sine of 30° is one-half. So, second option is correct.
PV × (1 + r/n)∧nt = FV
$70.00 × (1 + .16/4)∧4X25 = FV
$70.00 × (1 + .04)∧100 = FV
$70.00 × 50.50 = FV
$3535 =FV
The final amount is $3535
Answer:
b ≤ 26/3
Step-by-step explanation:
All we have to do is divide both sides by 3
3x/3 ≤ 26/x
x ≤ 8.67
Answer:
x=-9
Step-by-step explanation:
3-2=1*x=2=x+2=-7=x=-9
