Question

CAN SOMEONE HELP ME WITH MY ALGEBRA 1.

Answer 1

Answer:

-5

Step-by-step explanation:

$\frac{7-2^{2}+17}{-14+(2)(5)}$

Multiply 2 · 2 = 4

$\frac{7-4+17}{-14+(2)(5)}$

Subtract 4 - 7 = 3

$\frac{3+17}{-14+(2)(5)}$

Add 3 + 17 = 20

$\frac{20}{-14+(2)(5)}$

Multiply 2 · 5 = 10

$\frac{20}{-14+10}$

Add -14 + 10 = -4

$\frac{20}{-4}$

Divide 20 ÷ 4 = -5

$-5$

Answer 2

Answer:

-5

Step-by-step explanation:

$\frac{(7-2x^{2} )+17}{-14+2*5}$

Find 2 to the power of 2 which is 4

$\frac{7-4+17}{-14+2*5}$

Subtract 4 from 7 to get 3

$\frac{3+17}{-14+2*5}$

Add 3 and 17 to get 20

$\frac{20}{-14+2*5}$

Multiply 2 and 5 to get 10

$\frac{20}{-14+10}$

Add -14 and 10 to get -4

$\frac{20}{-4}$

Divide 20 by -4 to get -5

Sooo the answer is -5

hope this helps :)