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m_a_m_a [10]
3 years ago
10

Solving the right triangle ‼️ (Round to the nearest tenth) can someone help me find A,a, and b❓

Mathematics
2 answers:
Gekata [30.6K]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the 2 angles from 180 for A

A = 180° - (50 + 90)° = 180° - 140° = 40°

Use the cosine and sine ratios in the right triangle for a and b

cos50° = \frac{adjacent}{hypotenuse} = \frac{a}{26}

Multiply both sides by 26

26 × cos50° = a, thus

a ≈ 16.7 ( to the nearest tenth )

sin50° = \frac{opposite}{hypotenuse} = \frac{b}{26}

Multiply both sides by 26

26 × sin50° = b, thus

b ≈ 19.9 ( to the nearest tenth )

Nataliya [291]3 years ago
3 0

A is 40 degrees imma edit this or do it in comments the other ones

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