Question

Solving the right triangle ‼️ (Round to the nearest tenth) can someone help me find A,a, and b❓

Answer 1

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the 2 angles from 180 for A

A = 180° - (50 + 90)° = 180° - 140° = 40°

Use the cosine and sine ratios in the right triangle for a and b

cos50° = $\frac{adjacent}{hypotenuse}$ = $\frac{a}{26}$

Multiply both sides by 26

26 × cos50° = a, thus

a ≈ 16.7 ( to the nearest tenth )

sin50° = $\frac{opposite}{hypotenuse}$ = $\frac{b}{26}$

Multiply both sides by 26

26 × sin50° = b, thus

b ≈ 19.9 ( to the nearest tenth )

Answer 2

A is 40 degrees imma edit this or do it in comments the other ones