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kozerog [31]
2 years ago
9

What is the solution to 0.5 (4x -10) = 2x +4

Mathematics
1 answer:
Alisiya [41]2 years ago
8 0

Answer:

if you are looking for an equation it would be y=3x+4

Step-by-step explanation:

Please mark brainliest

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PLZ HELP!
AnnyKZ [126]

Answer:

$0.25

Step-by-step explanation:

Site A pays ...

... $0.65 × 5 = $3.25

Site B pays ...

... y = 0.60·5 = 3.00 . . . dollars

Site A pays more by ...

... $3.25 - 3.00 = $0.25

_____

You can also look at the difference in unit rates. Site A pays $0.65 per photo, while site B pays $0.60 per photo, a difference of $0.65 - 0.60 = $0.05 per photo. Then 5 photos will be worth $0.05 × 5 = $0.25 more at Site A.

4 0
3 years ago
Rotations Please help me.
Trava [24]

Answer:

  see attached

Step-by-step explanation:

You can do these yourself fairly easily. Copy the figure and the coordinate axes onto a piece of tracing paper (tissue paper or even facial tissue will work, too), then rotate the copied figure 90° clockwise.

Line up the origin of the axes and make sure the axes you drew line up with the ones on the original figure. For 90° clockwise rotation, what was the +y axis will now align with the +x axis. Copy the rotated figure from the tracing paper back to the graph on your problem page in its new location. (You can cut out the figure, if necessary. Just be sure to make note of the position relative to the axes.)

This sort of physical activity reinforces the thinking you need to do to mentally rotate the figures. It is worth the effort.

7 0
3 years ago
A circle is centered at J(3, 3) and has a radius of 12.
stealth61 [152]

Answer:

(-6,\, -5) is outside the circle of radius of 12 centered at (3,\, 3).

Step-by-step explanation:

Let J and r denote the center and the radius of this circle, respectively. Let F be a point in the plane.

Let d(J,\, F) denote the Euclidean distance between point J and point F.

In other words, if J is at (x_j,\, y_j) while F is at (x_f,\, y_f), then \displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}.

Point F would be inside this circle if d(J,\, F) < r. (In other words, the distance between F\! and the center of this circle is smaller than the radius of this circle.)

Point F would be on this circle if d(J,\, F) = r. (In other words, the distance between F\! and the center of this circle is exactly equal to the radius of this circle.)

Point F would be outside this circle if d(J,\, F) > r. (In other words, the distance between F\! and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between J and F:

\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145}  \end{aligned}.

On the other hand, notice that the radius of this circle, r = 12 = \sqrt{144}, is smaller than d(J,\, F). Therefore, point F would be outside this circle.

5 0
3 years ago
Julia has 4 gallons 2 quarts of water. Ally needs the same amount of water but only has 12 quarts. How much more water does ally
skad [1K]
Answer: Ally would need 6 more quarts of water.
Explanation: Since 4 quarts equal 1 gallon, 4*4 = 16 + 2 = 18, Julia would have 18 quarts. Subtract 12 from 18 to get 6 quarts. 
5 0
3 years ago
Factor 64 - P.<br> (8 - x(8 - x)<br> (8 + x (8 - x)<br> (X + 8)(x-8)
muminat

Question:

Factor 64-x^2

(8 - x)(8 - x)

(8 + x) (8 - x)

(X + 8)(x-8)

Answer:

Option B: (8+x)(8-x) is the factor

Explanation:

Given that the expression is 64-x^2

We need to find the factor of the given expression.

Let us rewrite the expression as 8^2-x^{2}

Since the expression is of the form a^2-b^2, let us use the identity a^2-b^2=(a+b)(a-b)

where a = 8 and b = x

Substituting the values in the identity, then the expression can be written as

8^2-x^{2}=(8+x)(8-x)

Thus, the factor of the expression is (8+x)(8-x)

Hence, Option B is the correct answer.

4 0
3 years ago
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