Answer: Arc CE measures 62 units
Step-by-step explanation: What we have in the question is a circle with two secants ABC and ADE. The two secants have been extended such that two arcs have been formed which are, major arc CE (that is, 4x - 10) and minor arc BD (that is 26).
When you have a circle with two intersecting secants, the angle x (that is angle CAE) is derived as half of the difference of the two intercepted arcs. That is;
Angle x = 1/2 [CE - BD)
Angle x = 1/2 [ (4x - 10) - 26]
Angle x = 1/2(4x - 36)
Cross multiply and we now have
2x = 4x - 36
Collect like terms and we now have
36 = 4x - 2x
36 = 2x
Divide both sides by 2
18 = x
Having calculated x as 18, where arc CE equals 4x - 10, then substitute for the value of x.
CE = 4(18) - 10
CE = 72 - 10
CE = 62
A random sample (Sample 1) of the Mercedes's average driving speed (km/h) is: 120, 142, 142, 165, 132, 130, 156, 136, 167, 139,
ziro4ka [17]
The median of Mercedes' speed is 144 km/h.
The median of Audi's speed is ~133,6 km/h.
Answer:
The answer would be -4x - 42.
Step-by-step explanation:
Goal: Simplify the equation.
- You need to distribute the - sign where it isn't. So the equation should look like this now: 4(-3-5)+-1(10+4x).
- Now multiply -1(0+4x): (-1)(10) + -1(4x) to get 4(-3-5) +-10+-4x
- Now multiply 4(-3-5): (4)(-3)= -12 / (4)(5) = 20 / -12-20 = -32
- The equation should now look like: -32 + -10 + -4x
- Next, we need to combine like terms and since the like terms are -32 and -10, the equation should look like: -4x + (-32 + -10).
- Add -32 with -10: -32 + -10 = -42.
- You can't do anything with the -4x so therefore, the equation would be -4x - 42.
Answer: [a] 95% confidence interval = 4.4 < Ẍ <9.2
[b] margin of error = ± 2.4
Step-by-step explanation:
here let us carefully look into this problem,
from the question, we have that Ẍ = 6.8, and SE = 1.2
let us begin
(a). asked to calculate the 95% confidence interval we have;
95% C.I = Ẍ ± 2 (SE) = 6.8 ± 2(1.2) = 6.8 ± 2.4
95% C.I = (4.4, 9.2)
this gives the confidence interval to be (4.4 < Ẍ < 9.2).
(b). the error margin is ± 2.4, which implies that our estimate of 6.8 pounds is within 2.4 pounds of the true mean weight gain for the population.
cheers i hope this helped a great deal !!1
