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liq [111]
2 years ago
6

Evaluate 16x^{0} if x = -3

Mathematics
1 answer:
krok68 [10]2 years ago
8 0

Step-by-step explanation:

16

hope it helps u........

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PLZ HELP AND HURRY!!!!
yuradex [85]

Answer: x=30, Good Luck!

Step-by-step explanation:

45/27 = 1.6666666...

1.66666...(18) = 30

8 0
2 years ago
Rob is saving to buy a new MP3 player. For every $14 he earns babysitting, he saves $6. On Saturday, Rob earned $28 babysitting.
ddd [48]
He saved $12 from Saturday babysitting
7 0
3 years ago
Read 2 more answers
Which number goes in the box to make this a true sentence? 65 × 32 = (65 × 30) + (65 × ) PLZZ HELP!
lutik1710 [3]
The answer would be 2.

65 x 32 = 2080.

(65 × 30) = <span>1950</span><span>
(65 × 2) = 130

1950 + 130 = 2080

To make this easier, you can 30 from 32.</span>
7 0
3 years ago
Pls pls pls pls pls help ill mark brainliest​
Marrrta [24]

Answer:

Y= 0. There is two that says that so I don't know if it's A or C

7 0
2 years ago
The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. Assu
m_a_m_a [10]

Answer: 0.0170

Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

i.e. \mu=23.50

\sigma=5

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let \overline{x} be the sample mean.

Formula : z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

Then, the probability that the sample mean is at least $25.00 will be :-

P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z

Hence, the likelihood the sample mean is at least $25.00= 0.0170

5 0
3 years ago
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