I believe the answer is B
Answer:
10 quarters = $2.50
10 nickels = $0.50
that leaves $0.20 for other coins (dimes / pennies)
Step-by-step explanation:
First, suppose she has only quarters and nickels and no other coins. Then if C is the identical number of coins of each type, then 5C + 25C = 320, so 30C = 320 and 3C = 32, but there is no integer solution to this. So she must have at least one other type of coin.
Assume she has only quarters, nickels, and dimes. Then if D is the number of dimes, 5C + 25C + 10D = 320, which means 30C + 10D = 320, or 3C + D = 32. The smallest D can be is 2, leaving 3C = 30 and thus C = 10. So in this scenario she would have 10 quarters, 10 nickels, and two dimes to make $2.50 + $0.50 + $0.20 = $3.20.
This has to be the highest number, because if she had 11 quarters and 11 nickels, that alone would add up to 11(0.25) + 11(0.05) = $3.30, which would already be too much.
Let x, y and z denote the weighs of car X, car Y and car Z, respectively.
We know that car X weighs 136 more than car Z, this can be express by the equation:
We also know that Y weighs 117 pounds more than car Z, this can be express as:
Finally, we know that the total weight of all the cars is 9439, then we have:
Hence, we have the system of the equations:
To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:
Now that we have the value of z we plug it in the first two equations to find x and y:
Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.
The values of x at wich F(x) has local minimums are x = -2 and x = 4, and the local minimums are:
<h3>
What is a local maximum/minimum?</h3>
A local maximum is a point on the graph of the function, such that in a close vicinity it is the maximum value there. So, on an interval (a, b) a local maximum would be F(c) such that:
c ∈ (a, b)
F(c) ≥ F(x) for ∀ x ∈ [a, b]
A local minimum is kinda the same, but it must meet the condition:
c ∈ (a, b)
F(c) ≤ F(x) for ∀ x ∈ [a, b]
A) We can see two local minimums, we need to identify at which values of x do they happen.
The first local minimum happens at x = -2
The second local minimum happens at x = 4.
B) The local minimums are given by F(-2) and F(4), in this case, the local minimums are:
If you want to learn more about minimums/maximums, you can read:
brainly.com/question/2118500
