Question

Factor 6^3 * 28^3 into the product of its prime factors by first factoring 6 and 28 completely. Enter only the fully

Answer 1

$\\ \rm\longmapsto 6^3\times 28^3$

$\\ \rm\longmapsto (2\times 3)^3\times (7\times 2\times 2)^3$

$\\ \rm\longmapsto 2^3\times 3^3\times 7^3\times 2^3\times 2^3$

$\\ \rm\longmapsto 2^{3+3+3}3^37^3$

$\\ \rm\longmapsto 2^93^37^3$

Answer 2

Answer:

• 2⁹*3³*7³

Step-by-step explanation:

• 6³*28³ =
• (2*3)³*(2*2*7)³ =
• 2³*3³*2³*2³*7³ =
• 2⁹*3³*7³