Answer:
(8n)(-77)=-77(n*8)
We move all terms to the left:
(8n)(-77)-(-77(n*8))=0
We add all the numbers together, and all the variables
8n(-77)-(-77(+n*8))=0
We multiply parentheses
-616n-(-77(+n*8))=0
We calculate terms in parentheses: -(-77(+n*8)), so:
-77(+n*8)
We multiply parentheses
-616n
Back to the equation:
-(-616n)
We get rid of parentheses
-616n+616n=0
We add all the numbers together, and all the variables
=0
n=0/1
n=0
the property is Associative Property
Step-by-step explanation:
this one was kinda hard pls let me know it its right or not
Answer:
A) The best way to picture this problem is with a probability tree, with two steps.
The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.
The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.
If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.
If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.
B) So a person can have a red marble and a blue marble in two ways:
1) Picking the red first and the blue last
2) Picking the blue first and the red last
C) P(R&B) = 3/5 = 60%
Step-by-step explanation:
C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5
Answer:
60
Step-by-step explanation:
200 x 0.3 = 60
For this case we have that by definition, the volume of a cube is given by:

Where:
l: It's the side of the cube
According to the statement data:

Substituting in the formula we have:

Thus, the shipping cube volume is
Answer:

Answer:
see below
Step-by-step explanation:
(ab)^n=a^n * b^n
We need to show that it is true for n=1
assuming that it is true for n = k;
(ab)^n=a^n * b^n
( ab) ^1 = a^1 * b^1
ab = a * b
ab = ab
Then we need to show that it is true for n = ( k+1)
or (ab)^(k+1)=a^( k+1) * b^( k+1)
Starting with
(ab)^k=a^k * b^k given
Multiply each side by ab
ab * (ab)^k= ab *a^k * b^k
( ab) ^ ( k+1) = a^ ( k+1) b^ (k+1)
Therefore, the rule is true for every natural number n