Answer:
Step-by-step explanation:
Sample space is 36C4
Now, we want to know all of the combinations that have 1 digit in it.
So, we can have one here:
1XXX
X1XX
XX1X
XXX1
But we have 10 different digits to choose from. So, we need to introduce the combination term, nCr, where n is a list of all digits and r is how many we want.
Since we only want one, we will need 10C1 for the number of digits. But we need to choose three lowercases, so it becomes 10C1 × 26C3
Since it's a probability question, we need to divide that by our sample space, 36C4, and our percentage becomes 44%
-4, -2, -1, -0.8, 0.8, 3, 10
The two at the top technically means how many times the number in the bracket times ITSELF by, so its technically -3 x -3 which is +9 , cause a negative x negative = positive
Answer:
True
Step-by-step explanation:
A six sigma level has a lower and upper specification limits between
and
. It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:
.
The probability of defects is:

Well, the defects present in a six sigma level and a five sigma level are, respectively:
Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>
[1]
[2]
Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.