840
10% =84 (840/10)
5% =42 (84/2 or 840/20)
therefore 840+42=882
The answer is C. 5
This is the answer because
125 / 2 = 62.5
125 / 3 = 41.6_
125 / 5 = 25
125 / 7 = 17.86
As you can see 5 is the only number it can be divisible by.
Hope that helps!!
Answer:
1. Cosθ / SineθCosθ
2. Sineθ / Cos²θSineθ
3. Cosθ / Sineθ
4. Cos²θ + Sin²θ – Sin²θ
Step-by-step explanation:
1. SecθCotθ
Recall
Sec θ = 1/Cos θ
Cot θ = 1/Tan θ
But Tan θ = Sine θ / Cos θ
Thus,
Cot θ = 1 ÷ Sine θ / Cos θ
Cot θ = 1 × Cos θ / Sine θ
Cot θ = Cos θ / Sine θ
Therefore,
SecθCotθ = 1/Cos θ × Cos θ / Sine θ
SecθCotθ = Cosθ / SineθCosθ
2. SecθTanθCscθ
Recall
Sec θ = 1/Cos θ
Tan θ = Sine θ / Cos θ
Csc θ = 1/Sine θ
Thus,
SecθTanθCscθ =
1/Cosθ × Sineθ/Cosθ × 1/Sineθ
= Sineθ / Cos²θSineθ
3. Cscθ/Secθ
Recall
Csc θ = 1/Sine θ
Sec θ = 1/Cos θ
Thus,
Cscθ/Secθ = 1/Sine θ ÷ 1/Cos θ
= 1/Sine θ × Cos θ
= Cosθ / Sineθ
4. Cosθ / Secθ
Recall
Sec θ = 1/Cos θ
Cosθ / Secθ = Cosθ ÷ 1/Cosθ
= Cosθ × Cosθ
= Cos²θ
Recall
Cos²θ + Sin²θ = 1
Cos²θ = 1 – Sin²θ
But
1 = Cos²θ + Sin²θ
Thus,
Cos²θ = Cos²θ + Sin²θ – Sin²θ
Therefore,
Cosθ / Secθ = Cos²θ + Sin²θ – Sin²θ
360 is the answer
72000/x=200
72000/200=x
x=360
Answer:
Time machine one = 3.56
Time machine two = 4.56
Step-by-step explanation:
Let machine 2 do the job in x hours
Let machine 1 do the job in x - 1 hours.
The general formula for this problem is
Time = A*B/(A + B)
Givens
Time = 2 hours
B = x hours alone
A = x - 1 hours alone.
#################
x *( x - 1)
======= = 2
(x + x - 1)
(x^2 - x)/(2x - 1) = 2
x^2 - x = 2(2x - 1)
x^2 - x = 4x - 2
x^2 - 5x + 2 = 0
a = 1
b = - 5
c = 2
This gives 2 roots
x = 4.56
x = 0.43
The second root will not work because when 1 is subtracted from 0.43 the time give will be minus, which won't work.
Time for machine 2 is 4.56
The time for machine 1 is 3.56
Check
(A * B)/(A + B) = 2
A = 4.56
B = 3.56
Time = 4.56*3.56/(4.56 + 3.56)
Time = 16.2336/(8.12)
Time = 1.9992
The rounding error in the check comes from the rounding error in the times.
