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2 years ago

Someone PLEASE help with these as fast as you can. thank you so much

Mathematics

1 answer:

nika2105 [10]2 years ago

3 0

Answer:

Step-by-step explanation:

1) 945,235.321

9 is in hundred thousand's place.Its value = 900,000 - nine hundred thousand

4 is in ten thousand's place.It's value = 40,000 - Forty thousand

5 is in thousand's place. It's value = 5,000 - Five thousand

2 is in hundred's place. It's value = 200 - two hundred

3 is in ten's place.It's value = 30 - thirty

5 is in one's place. It's value = 5 - Five

3 is in tenth's place.It's value = 0.3 - point 3

2 is in hundredth's place.It's value = 0.02 - point zero two

1 is in thousandth's place. Its value = 0.001 - point zero zero one

735.284

8 is in hundredth place.It's value = 0.08

5 is in one's place. It's value = 5

2 is in tenth place.Its value = 0.2

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2 years ago

The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is

qwelly [4]

Answer:

Step-by-step explanation:

Given an acute triangle in which the longest side measures 30 inches; and the other two sides are congruent.

Consider the attached diagram

AB=BC=x

However to be able to solve for x, we form a right triangle with endpoints A and C.

Since the hypotenuse is always the longest side in a right triangle

Hypotenuse, AC=30 Inches

Using Pythagoras Theorem

$30^2=x^2+x^2\\900=2x^2\\x^2=450\\x=\sqrt{450}\\x=21.21$ inches$

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2 years ago

Eric was rock climbing. At one point, he stopped and climbed straight down 2\dfrac{1}{2}2 2 1 2, start fraction, 1, divided by

podryga [215]

Answer:

Hence, Eric's elevation changed $4\frac{1}{4}$ meters above. So after the 2 moves, he is up by $4\frac{1}{4}$ meters.

Step-by-step explanation:

Let us assume "negative" as climbing up and "positive" as climbing up. Here we need to find the change in elevation.

$2\frac{1}{2}$ meters down means $-2\frac{1}{2}$ .
$6\frac{3}{4}$ meters up means $+6\frac{3}{4}$ .

Now we have:

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2 years ago

Show work and solve for √ ( 5 x − 9 ) − 1 = x.

Mandarinka [93]

sqrt (5x - 9) - 1 = x

sqrt(5x - 9) = x + 1

Square both sides:_

5x - 9 = x^2 + 2x + 1

x^2 - 3x + 10 = 0

(x - 5)(x + 2) = 0

x = 5 or -2.

Lets look for for any extraneous solutions:-

x = 5 ; sqrt (5*5-9) - 1 = sqrt16 - 1 = 3 and x = 3 (right hand side of equation)

so x = 5 is a solution

x = -2: sqrt(5*-2 - 9) - 1 = sqrt (-19) - 1 and x = -2 so this is extraneous

Answer:- One solution x = 5

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3 years ago

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