<span>With 1026 being the mean score on the SAT and StDev of 209, Jessica has a score of 799/209 z-scores above the mean. Her z-score would be 3.823. The mean of the ACT and StDev are 20.8 and 4.8, respectively. A 28 ACT score would be 7.2/4.8 z-scores above the mean, for a z = 1.500. This means that Jessica has the higher z-score.</span>
Answer:
D. 578pi
Step-by-step explanation:
Sorry if that's wrong
<u>Use the distributive property to solve. Multiply the two by every term in the parentheses and then combine alike terms.</u>
-6x^4y^5-15x^3y^2+9x^2y^3
The GCF OF -6, -15, & 9, is -3
The GCF OF x's is x^2
The GCF OF y's is y^2
These are the number of x's and y's that each term has.
-3x^2y^2(2x^2y^3+5x-3y)
LETTER B
