Ok so first we need to under stand that 60 minutes is equivalent to 1 hour, by knowing this we should be able to answer the following. Our first box which needs to be filled in asking how many hours are in 300 minutes, well let’s figure this out. So we know that in 60 minutes it will be equivalent to one hours, so in order to find how many minutes are in 300 minutes we would divide 300 by 60 which give a us 5. Therefore causing the second box to me 5 hours. Our next and final box is asking how many hours are in four minutes well this one is a little harder than our previous one but I’ll help you through it. By following the same procedure as we did the previous question we are going to divide 4 by 60 and we know that dividing like so we are going to get a decimal but that’s ok it’s going to give us the answer we need to fill in the box. By dividing like so we should get a long decimal that look that this 0.066666666666667. I am going to simply this down to 0.0667. Causing my last box to be 0.667.
Summary:
second box: 5 hours
Third box: 0.0667 hours
Hope this helps!!!
Please tell me if I have made an error, I enjoy learning from my mistakes:)
Have a great rest of your day❤️
Answer:
3/14 chance first draw
Step-by-step explanation:
There are 14 jellybeans in all, you won’t be replacing so the probability will change with each draw.
Probability the 1st draw is red = 3/14.
Probability the 2nd draw is red = (3–1)/(14–1) = 2/13.
Probability the 3rd draw is red = (2–1)/(13–1) = 1/12.
3/14 x 2/13 x 1/12 = 6/2184 = 1/364 is approximately 0.27%, pretty rare.
I would write the missing variable as x. It's what everyone uses.
Anyway, 91 divided by x is 65.
The way we can do this is reverse 65 and x.
91 divided by 65 = x.
91 divided by 1.4 = 65
65 x 1.4 = 91
x (or ?) = 1.4
Answer:
A=SqRt(c^2-b^2)
Step-by-step explanation:
a^2 + b^2 = c^2
rearrange to solve for a^2
a^2= c^2-b^2
take the square root of each side
a= square root (c^2-b^2)
<h3>
Answer: Check out the diagram below.</h3>
Explanation:
Use your straightedge to extend segment AB into ray AB. This means you'll have it start at A and go on forever through B. Repeat these steps to turn segment AC into ray AC.
The two rays join at the vertex angle A. Point A is the center of the universe so to speak because it's the center of dilation. We consider it an invariant point that doesn't move. Everything else will move. In this case, everything will move twice as much compared to as before.
Use your compass to measure the width of AB. We don't need the actual number. We just need the compass to be as wide from A to B. Keep your compass at this width and move the non-pencil part to point B. Then mark a small arc along ray AB. What we've just done is constructed a congruent copy of segment AB. In other words, we've just double AB into AB'. This means the arc marking places point B' as the diagram indicates.
The same set of steps will have us construct point C' as well. AC doubles to AC'
Once we determine the locations of B' and C', we can then form triangle A'B'C' which is an enlarged copy of triangle ABC. Each side of the larger triangle has side lengths twice as long.
Note: Points A and A' occupy the same exact location. As mentioned earlier, point A doesn't move.
