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professor190 [17]
2 years ago
14

2.01 × 1015 and 2.8 × 1013 which is larger

Mathematics
2 answers:
Eduardwww [97]2 years ago
7 0

Answer:

tertertert

Step-by-step explanation:

tretwerrrewrew

Ronch [10]2 years ago
7 0

2.01*1015=2O40.15
While
2.8*1013= 2836.4
Which means the second is the answer
If you meant 10 raise to the power of 15 and 10 raised to the power of 13 then the answer will be the first one.


I hope this helps pls mark as brainiest answer
Have a beautiful day
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Opposites are the same difference from zero!
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Definition of classic probability
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Classical probability is the statistical concept that measures the likelihood of something happening, but in aclassic sense, it also means that every statistical experiment will contain elements that are equally likely to happen.
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2 years ago
A right square pyramid with base edges of length $8\sqrt{2}$ units each and slant edges of length 10 units each is cut by a plan
seropon [69]

Answer:

32 unit^{3}

Step-by-step explanation:

Given:

  • The slant length 10 units
  • A right square pyramid with base edges of length 8\sqrt{2}

Now we use  Pythagoras to get the slant height in the middle of each triangle:

\sqrt{10^{2 - (4\sqrt{2} ^{2} }) } = \sqrt{100 - 32} = \sqrt{68}  units

One again, you can use Pythagoras again to get the perpendicular height of the entire pyramid.

\sqrt{68-(4\sqrt{2} ^{2} )} = \sqrt{68 - 32} = 6 units.

Because slant edges of length 10 units each is cut by a plane that is parallel to its base and 3 units above its base. So we have the other dementions of the small right square pyramid:

  • The height 3 units
  • A right square pyramid with base edges of length 4\sqrt{2}

So the volume of it is:

V  = 1/3 *3* 4\sqrt{2}

= 32 unit^{3}

5 0
3 years ago
What is the area of a triangle for one of the legs being 3in and the hypotenuse being 9in
elena55 [62]

The area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches is 12.727 square inches

<em><u>Solution:</u></em>

Given that to find area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches

From given information,

Let "c" = hypotenuse = 9 inches

Let "a" = length of one of the leg of triangle = 3 inches

To find: area of triangle

<u><em>The area of triangle when hypotenuse and length of one side of triangle is given:</em></u>

A = \frac{1}{2} a \sqrt{c^2 - a^2}

Where, "c" is the length of hypotenuse

"a" is the length of one side of triangle

Substituting the given values we get,

A = \frac{1}{2} \times 3 \times \sqrt{9^2 - 3^2}

A =\frac{1}{2} \times 3 \times \sqrt{81-9}\\\\A =\frac{1}{2} \times 3 \times \sqrt{72}\\\\A =\frac{1}{2} \times 3 \times 8.48528\\\\A = \frac{1}{2} \times 25.45584\\\\A = 12.727

Thus area of triangle is 12.727 square inches

5 0
2 years ago
Solve each of the following equations for the given variable using proper algebraic notation. Show ALL work for full marks.
icang [17]

Answer:

3x=42

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divide 6 to both sides

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add 6 to both sides

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divide 4 to both sides

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Step-by-step explanation:

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