Answer:
x = 5m/s
Step-by-step explanation:
Distance flying out = 12 km (headwind)
Distance flying back = 12 km (tailwind)
total distance = 12 + 12 =24 km
wind speed = 1km/h
speed going out (with headwind) = (x - 1) km/h
speed coming back (with tailwind) = (x + 1) km/h
Time taken to go out = distance going out / speed going out
= 12 / (x-1)
Time taken to come back = distance coming back / speed coming back
= 12 / (x+1)
total time = time taken to go out + time taken to come back
5 =[ 12/(x-1) ] + [ 12/(x-1)]
expanding this, we will get
5x² - 24x - 5 = 0
solving quadratic equation, we will get
x = -1/5 (impossible because speed cannot be negative)
or
x = 5 (answer)
Answer:
10y=27+7
10y=34
y=34/10
y=3.4
Step-by-step explanation:
Firstly 7 is added to 27
Then adding 7 and 27
Dividing 34 by 10
Answer:
the solution is x = 2 and y = 4 OR (2,4)
Step-by-step explanation:
From the question
Equation 1: 3x-2y= -2
Equation 2: 3x + y = 10
Subtract equation 1 from equation 2, that is
3x + y = 10 - (3x -2y = -2)
You get
3x - 3x + y - (-2y) = 10 - (-2)
0 + y + 2y = 10 + 2
3y = 12
Divide both sides by 3
∴ y = 12/3
y = 4
Substitute the value of y into equation 2 to get x
3x + y = 10
3x + 4 = 10
Then,
3x = 10 - 4
3x = 6
Divide both sides by 3
∴ x = 6/3
x = 2
Hence, the solution is x = 2 and y = 4
Answer:Combine like terms
3
+
5
−
=
9
−
7
+
1
2
{\color{#c92786}{3x}}+5{\color{#c92786}{-x}}=9x-7+12
3x+5−x=9x−7+12
2
+
5
=
9
−
7
+
1
2
{\color{#c92786}{2x}}+5=9x-7+12
2x+5=9x−7+12
2
Add the numbers
3
Subtract the same term from both sides of the equation
4
Simplify
5
Subtract the same term from both sides of the equation
6
Simplify
7
Divide both sides of the equation by the same term
8
Simplify
HOPE THIS HELPS :)
Step-by-step explanation:
3x + 1y = ¹/₃ ⇒ 9x + 3y = 1
2x - 3y = 2²/₃ ⇒ 2x - 3y = 2²/₃
11x = 3²/₃
11 11
x = ¹/₃
3x + y = ¹/₃
3(¹/₃) + y = ¹/₃
1 + y = ¹/₃
- 1 - 1
y = ⁻²/₃
(x, y) = (¹/₃, ⁻²/₃)
