1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex_Xolod [135]
2 years ago
5

PLEASE HELP!!!

Mathematics
1 answer:
IrinaVladis [17]2 years ago
8 0
44.


The closer it gets to -19, the closer the number goes to 44. It never hits it exactly though, but based off the trend (43.95, 43.995, 43.9995) we can tell that it gets closer to 44 each time.


Hope this helps! (:
You might be interested in
Excited about the success of celebrity​ stamps, post office officials were rumored to have put forth a plan to institute two new
SVETLANKA909090 [29]

Answer:

E=2.8 m-40

Step-by-step explanation:

We konw that  30°E=25°M and 310°E=125°M

so if we want to write an ecuation that linearly relates E with M, we can use the formula of the line that crosses two points:

Y-y1= (y2-y1)/(x2-x1)*(X-x1)

In thts case:

  • Y=E
  • y1= E1= 30
  • y2= E2=310
  • x1= M1= 25
  • x2=M2=125

so

E-E1= (E2-E1)/(M2-M1)* (M-M1)

E-30 = (310-30)/(125-25)*(M-25)

E-30 =280/100 *(M-25)

E-30 =2.8 M- 280*25/100

E-30 =2.8 M-70

E= 2.8 M-70+30

E=2.8 M-40

Good luck!

8 0
3 years ago
An isosceles triangle has an area of 32 cm2, and the angle between the two equal sides is 5π/6. Find the length of the two equal
taurus [48]
The area of a triangle can be determined by knowing 2 sides and their included angle of a certain triangle. Since both sides are equal, then they would just be denoted by a squared entity. This is done as follows:

A = x² sin∅
32 = x² sin (5*pi/6)

Make sure your calculator is in rad form.

32 = x² (1/2)
x = 8

Thus, each side is 8 cm. 
7 0
3 years ago
The table shows the cost of downloading songs.
Sonbull [250]

Answer:


Step-by-step explanation:

rate of change=cost per song

so the first option


3 0
3 years ago
HELP PLEASEEEEEEEEEEE
professor190 [17]
Question 5:
x/3=6
x=3(6)
x=18

Question 4:
2.3k=4.83
k=4.83/2.3
k=2.1

Question 6:
y=3/4-1/2
y=1/4

Question 2:
8r=24
r=3

Hope this helps!! :)
4 0
2 years ago
Suppose that a function​ f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence
Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

\lim_{x \to c} \frac{x^2-cx}{(x-c)}

We can simplify it

\lim_{x \to c} \frac{x(x-c)}{(x-c)}

=\lim_{x \to c} x

=c

so, we can see that limit exist and it's value defined

case-2:

\lim_{x \to c} \frac{1}{(x-c)}

Left limit is

\lim_{x \to c-} \frac{1}{(x-c)}

=-\infty

Right Limit is

\lim_{x \to c+} \frac{1}{(x-c)}

=+\infty

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0
3 years ago
Other questions:
  • What is the fancy name (symbol) for the ratio of c/d?
    11·1 answer
  • Marcus stays in France and the cost of a room is 75 euros per night. 1 euro = 1.29 dollars. What is the cost of Marcus' room if
    6·1 answer
  • What is the answer math problem ___-30-7 1/4= 21 2/3
    15·1 answer
  • Two scientists are running experiments testing the effects of a vaccine on different control groups. The results are shown in th
    15·2 answers
  • A machine produces photodetectors in pairs. Tests show that the first photo detector is acceptable with probability 3/5. When th
    6·1 answer
  • IN 5 *5 + a * 64 is 5 to 5 then 8 64 that add the a at the end
    14·1 answer
  • A clothing store is having a one
    6·1 answer
  • Solve the following system of linear equations by using the Elimination Method:
    9·1 answer
  • NEED HELP Solve: 3x + (2 - 4x); when x = 5 *
    7·2 answers
  • Solve the inequality: 1/3x + 8 _< 11
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!