Using proportions and the information given, it is found that:
- The class width is of 14.375.
- The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
- The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.
-------------------------
- Minimum value is 19.
- Maximum value is of 134.
- There are 8 classes.
- The classes are all of equal width, thus the width is of:

-------------------------
The intervals will be of:
19 - 33.375
33.375 - 47.750
47.750 - 62.125
62.125 - 76.500
76.500 - 90.875
90.875 - 105.250
105.250 - 119.625
119.625 - 134.
- The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
- The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.
A similar problem is given at brainly.com/question/16631975
Between 2 and 3, after the 2 1/4 point, but before the halfway point.
Divide 2 by 5.
you get .4
to make a number a percent, you shift the decimal two placed to the right.
so 2/5=.4=40%
Answer:
To find the area of a regular hexagon, or any regular polygon, we use the formula that says Area = one-half the product of the apothem and perimeter. As shown below, this means that we must find the perimeter (distance all the way around the hexagon) and the measure of the apothem using right triangles and trigonometry. Area of a Hexagon
Step-by-step explanation:
Answer:
$100
Step-by-step explanation:
$80=4/5 of her original money
(5/4)*80=original amount
=100