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sesenic [268]
3 years ago
6

Help me with my hw pleaseeee​

Mathematics
1 answer:
Sidana [21]3 years ago
5 0

Answer:

10 -angles CGD and FGE

11-FGB and EGD

12- BGC and CGD

13-FGB and BGD

14- AGB and BGC

15- EGD

You might be interested in
12. Find x. (x + 20)° (5x - 8)°​
ololo11 [35]

Answer:

<h2>x = 7</h2>

Step-by-step explanation:

Simplifying

x + 20 = 5x + -8

Reorder the terms:

20 + x = 5x + -8

Reorder the terms:

20 + x = -8 + 5x

Solving

20 + x = -8 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.

20 + x + -5x = -8 + 5x + -5x

Combine like terms: x + -5x = -4x

20 + -4x = -8 + 5x + -5x

Combine like terms: 5x + -5x = 0

20 + -4x = -8 + 0

20 + -4x = -8

Add '-20' to each side of the equation.

20 + -20 + -4x = -8 + -20

Combine like terms: 20 + -20 = 0

0 + -4x = -8 + -20

-4x = -8 + -20

Combine like terms: -8 + -20 = -28

-4x = -28

Divide each side by '-4'.

x = 7

Simplifying

x = 7

8 0
3 years ago
Which expression is equivalent to<br> 0 +<br> 2<br> 29<br> C+3<br> C+2<br> C+3<br> C+2
Kryger [21]

Answer:

C+3

Step-by-step explanation:

6 0
3 years ago
Round 123,949 to the underlined point. 4 is highlighted
ehidna [41]

\\ \sf\longmapsto 123,949

  • 9 is greater than 5

\\ \sf\longmapsto 123,95

  • 5=5

\\ \sf\longmapsto 123,9

  • 9 is greater than 5

\\ \sf\longmapsto 124

  • 4 is less than 5

\\ \sf\longmapsto 12

  • 2 is less than 5

\\ \sf\longmapsto 1

Note

Write the number until underlined point.I did it till end

5 0
3 years ago
Read 2 more answers
X/8 - I/2 = 6 what is the answer to x
notka56 [123]
X/8-1/2=6
X/8=6+1/2=13/2
X/8=52/8
X=52
3 0
3 years ago
Find the domain over which the function y = x + 6x is monotonic increasing.
iragen [17]

Answer:

x > -3

\sf (-3, \infty)

Step-by-step explanation:

Domain: input values (x-values)

Monotonic increasing:  always increasing.  
A function is increasing when its graph rises from left to right.

The graph of a quadratic function is a parabola.  If the leading term is positive, the parabola opens upwards.  The domain over which the function is increasing for a parabola that opens upwards is values greater than the x-value of the vertex.

<u>Vertex</u>

Standard form of quadratic equation:  \sf y=ax^2+bx+c

\textsf{x-value of vertex}=\sf -\dfrac{b}{2a}

Given function:

\sf y=x^2+6x

Therefore, x-value of function's vertex:

\sf \implies x= -\dfrac{6}{2}=-3

<u>Final Solution</u>

The function is increasing when x > -3

\sf (-3, \infty)

4 0
2 years ago
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