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3 years ago

Help me with my hw pleaseeee

Mathematics

1 answer:

Sidana [21]3 years ago

5 0

Answer:

10 -angles CGD and FGE

11-FGB and EGD

12- BGC and CGD

13-FGB and BGD

14- AGB and BGC

15- EGD

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Jason consumes 1500 calories and needs to

Lubov Fominskaja [6]

Answer:

100*150=15000 calories

Step-by-step explanation:

100 times 150 is 15000 because you are multipling 2 people

I don't know if it is correct

just check and if it isn't then check some one elses work.

6 0

3 years ago

Is the number 8 odd or even?

Veseljchak [2.6K]

Hello there!

The number 8 is an even number, since it can be divided evenly by the number of 2.

Hope this helps and have a great day! :)

6 0

3 years ago

If you were to describe a translation of triangle , what information would you need to include in your description?

emmainna [20.7K]

You would need to have the information of how it translated, wether it was left or right, or up or down. you would also want the information of how far it translated.

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4 years ago

Use Simpson's Rule with n = 10 to approximate the area of the surface obtained by rotating the curve about the x-axis. Compare y

DiKsa [7]

The area of the surface is given exactly by the integral,

$\displaystyle\pi\int_0^5\sqrt{1+(y'(x))^2}\,\mathrm dx$

We have

$y(x)=\dfrac15x^5\implies y'(x)=x^4$

so the area is

$\displaystyle\pi\int_0^5\sqrt{1+x^8}\,\mathrm dx$

We split up the domain of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [4, 9/2], [9/2, 5]

where the left and right endpoints for the $i$ -th subinterval are, respectively,

$\ell_i=\dfrac{5-0}{10}(i-1)=\dfrac{i-1}2$

$r_i=\dfrac{5-0}{10}i=\dfrac i2$

with midpoint

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4$

with $1\le i\le10$ .

Over each subinterval, we interpolate $f(x)=\sqrt{1+x^8}$ with the quadratic polynomial,

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

Then

$\displaystyle\int_0^5f(x)\,\mathrm dx\approx\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It turns out that the latter integral reduces significantly to

$\displaystyle\int_0^5f(x)\,\mathrm dx\approx\frac56\left(f(0)+4f\left(\frac{0+5}2\right)+f(5)\right)=\frac56\left(1+\sqrt{390,626}+\dfrac{\sqrt{390,881}}4\right)$

which is about 651.918, so that the area is approximately $651.918\pi\approx\boxed{2048}$ .

Compare this to actual value of the integral, which is closer to 1967.

4 0

3 years ago

How to put -3x(4-6x) in distributive property

Rashid [163]

Answer:

-12x+18x²

Step-by-step explanation:

Given: $-3x(4-6x)$

Distributive property of multiplication under which a number is multiplied by the sum of two number, the first number can be distributed to both of those number.

∴ $-3x(4-6x)$

solving it by using distributive property

= $(-3x\times 4)-(-3x\times 6x)$