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Nataly [62]
3 years ago
5

Solve for x with an explanation pls

Mathematics
2 answers:
m_a_m_a [10]3 years ago
7 0
X=9

A squared + b squared = c squared

C is the hypotenuse (the side opposite of the right angle)

X*2 + square root of 63 squared = 12*2
Squaring 63 would cancel out with the square root. You are left with x*2 + 63 = 144. 144-63= 81. X*2=81 ; square root both sides. You are now left with x=9
Tatiana [17]3 years ago
6 0

Answer: 9

Step-by-step explanation:

Use Pythagorean's Theorem for a right triangle.

a^2+b^2=c^2

(\sqrt{63}) ^2+x^2=12^2\\63+x^2=144\\x^2=81\\x=9

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alisha [4.7K]
<h3>I'll teach you how to solve (1/5x-4+2y)+(2/5x+5-4y)</h3>

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(1/5x-4+2y)+(2/5x+5-4y)

Remove parentheses:

1/5x-4+2y + 2/5x+5-4y

Group like terms:

1/5x+2/5x+2y-4y-4+5

Add similar elements:

3/5x+2y-4y-4+5

Add similar elements:

3/5x-2y-4+5

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3x/5-2y-4+5

Add subtract the numbers:

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6 0
3 years ago
Please help me click the picture to see
artcher [175]
0.25x+97
Factoring:
Convert 0.25 to a fraction:
1/4x+97
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6 0
3 years ago
If the two legs of the right triangle are 5
yanalaym [24]

Answer:

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4 0
3 years ago
The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand
Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                         P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean strength of 50 items = 74.28

            \sigma = population standard deviation = 2.15

            n = sample of items = 50

            \mu = population mean tensile strength after machine was adjusted

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                  significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                 = [ 74.28-1.96 \times {\frac{2.15}{\sqrt{50} } } , 74.28+1.96 \times {\frac{2.15}{\sqrt{50} } } ]

                 = [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

<em>Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.</em>

8 0
3 years ago
A city survey of two neighborhoods asked residents whether they would prefer a new playground or a dog park.
const2013 [10]

Answer:

so if it is asking about the exact percentage then the answer is B but if it is the percentage in all the answer is D.

Step-by-step explanation:  My reasoning behind is that 70 percent of the neighborhood wants a playground if it is 40 to 17

3 0
3 years ago
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