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Tamiku [17]
2 years ago
15

Please help me with this following question​

Mathematics
1 answer:
natka813 [3]2 years ago
4 0

Answer:

yes

Step-by-step explanation:

f(x) = 2x³ - \frac{3}{2} x² - 4x + 6

g(x) = \frac{1}{2} ( 4x³ - 3x² - 8x + 12) ← multiply each term in the parenthesis by \frac{1}{2}

      = 2x³ - \frac{3}{2} x² - 4x + 6

     = f(x)

Then f(x) and g(x) are equal polynomials

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What is an internal and External angle
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Answer:

In geometry, an angle of a polygon is formed by two sides of the polygon that share an endpoint. For a simple (non-self-intersecting) polygon, regardless of whether it is convex or non-convex, this angle is called an interior angle (or internal angle) if a point within the angle is in the interior of the polygon. A polygon has exactly one internal angle per vertex. If every internal angle of a simple polygon is less than 180°, the polygon is called convex. In contrast, an exterior angle (or external angle) is an angle formed by one side of a simple polygon and a line extended from an adjacent side.

Step-by-step explanation:

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The common difference is 7
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Easy!
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3 years ago
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Step-by-step explanation:

5 0
3 years ago
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Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$
Blizzard [7]
\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}

a^{81}\equiv1^{81}\equiv1\pmod7

b^{91}\equiv2^{91}\pmod7

2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7
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2\equiv2\pmod7
\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7

c^{27}\equiv6^{27}\pmod7

6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7

\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7
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3 years ago
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