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Neko [114]
3 years ago
7

Anna has leaned a ladder against the side of her house. If the ladder forms a 72º angle with the ground and rests against the ho

use at a spot that is 6 meters high, approximately how far is the bottom of the ladder from the wall?
- 2 m

- 5 m

- 3 m

- 4 m

Mathematics
2 answers:
LuckyWell [14K]3 years ago
6 0

Answer:

(A) 2 meter

Step-by-step explanation:

It is given that the ladder forms a 72º angle with the ground and rests against the house at a spot that is 6 meters high.

Let the measure of bottom of the ladder from the wall be x, then using the trigonometry, we have

\frac{CB}{AB}=tan72^{\circ}

\frac{6}{x}=tan72^{\circ}

\frac{6}{x}=3.077

x=\frac{6}{3.077}

x=1.94

x≈2m

Thus, option A is correct.

ANTONII [103]3 years ago
6 0
Then u need to use tanФ=perpendicular/base
tan72°=6/x
3.077=6/x
x=1.949
x=2 m approx
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Find the solution to quadratic equation X^2+2x+5-0
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=x^2+2x+5

Step-by-step explanation:

X^2+2x+5-0

=X^2+2x+5+0

Combine Like Terms:

=X^2+2x+5+0

=(X^2)+(2x)+(5+0)

=X^2+2x+5

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3 years ago
What is the area of the triangle?<br> 16<br> 8<br> 10
sertanlavr [38]

Answer:

64

Step-by-step explanation:

Find the area of both triangles inside the bigger triangle and add them together.

Use the Pythagorean theorem to find the missing length of the leg in the smallest triangle:

a² + b² = c²

8² + b² = 10²

64 + b² = 100

36 = b²

6 = b

Calculate the area of the smaller triangle:

1/2(<em>b</em>x<em>h</em>)

1/2(6 x 8)

1/2(48)

24

Calculate the area of the bigger triangle:

<em>We know that the longer leg is 10 units because we were able to subtract the length of the smaller triangle's leg from 16.</em>

1/2(<em>b</em>x<em>h</em>)

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3 0
2 years ago
What is 18/25 as a decimal
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Step-by-step explanation:

Hope that helps :)

4 0
3 years ago
Read 2 more answers
Name a point that is between 50 and 60 units away from (7,-2) and state the distance between the two points.
laila [671]

Let the required point be (a,b)

The distance of (a,b) from (7,-2) is

= \sqrt{(a-7)^2+(b+2)^2}

But this distance needs to be betweem 50 & 60

So

50

Squaring all sides

2500 < (a-7)² + (b+2)² < 3600

Let a = 7

So we have

2500 < (b+2)² <3600

b+2 < 60    or  b+2 > -60   => b <58 or b > -62

Also

b+2 >50    or b + 2 < -50  => b >48 or B < -52

Let us take one value of b < 58 say b = 50

So now we have the point as (7, 50)

The other point is (7,-2)

Distance between them

= \sqrt{(7-7)^2+(50+2)^2}= \sqrt{(52)^2}=52

This is between 50 & 60

Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)


6 0
3 years ago
Read 2 more answers
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