The weight of each bag is 0.545 lb .
<h3>What is weight ?</h3>
Weight in maths is the value of the mass of an object on a measuring scale , It is measured in pound , ounce , kilogram etc.
It is given that
Total weight of green grapes = 5.65 lb
Total weight of red grapes = 3.07lb
Total weight = 5.65 +3.07 = 8.72 lb
Total number of bags = 16
the weight of each bag
= 8.72 / 16
= 0.545 lb
Therefore the weight of each bag is 0.545 lb .
The complete question is
Emilio bought 5.65lb of green grapes and 3.07lb of red grapes. He divided the grapes equally into 16 bags. If each bag of grapes has the same weight, how much does each bag weigh?
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Answer:
-4 to 3
Step-by-step explanation:
look at the first number in each set then find the smallest and the biggest that is how you find range
Substitute the variable for the value given.
11 - 3m becomes 11 - 3(2)
Now do the order of operations.
11 - 3(2) =
11 - 6 =
5
So, the answer is 5.
Call the notebooks x, and the pencils y.
<span>3x + 4y = $8.50 and 5x + 8y = $14.50 </span>
<span>Then just solve as simultaneous equations: </span>
<span>3x + 4y = $8.50 </span>
<span>5x + 8y = $14.50 </span>
<span>5(3x + 4y = 8.5) </span>
<span>3(5x + 8y = 14.5) </span>
<span>15x + 20y = 42.5 </span>
<span>15x + 24y = 43.5 </span>
<span>Think: DASS (Different Add, Similar Subtract). 15x appears in both equations so subtract one equation from the other. Eassier to subtract (15x + 20y = 42.5) from (15x + 24y = 43.5) </span>
<span>(15x + 24y = 43.5) - (15x + 20y = 42.5) = (4y = 1) which means y = 0.25. </span>
<span>Then substitue into equation : </span>
<span>15x + 20y = 42.5 </span>
<span>15x + 5 + 42.5 </span>
<span>15x = 42.5 - 5 = 37.5 </span>
<span>15x = 37.5 </span>
<span>x = 2.5 </span>
<span>15x + 24y = 43.5 </span>
<span>15(2.5) + 24(0.25) </span>
<span>37.5 + 6 = 43.5 </span>
<span>So x (notebooks) are 2.5 ($2.50) each and y (pencils) are 0.25 ($0.25) each.</span>
Answer:
- x² - 8x + 12
- x³ + 2x² - 15x - 36
- x³ -2x² - 15x
Step-by-step explanation:
#1) Find the polynomial with roots at 2 and 6
-
(x -2)(x - 6) = x² - 8x + 12
#2) Find the polynomial with a double root at -3 and another root at 4
-
(x+3)(x+3)(x-4) = (x²+6x+9)(x-4) = x³ + 2x² - 15x - 36
#3) Find the polynomial with roots 0, -3 and 5
- (x -0)(x+3)(x-5) = x(x²-2x - 15) = x³ -2x² - 15x