Answer:
The answer is 1/27
Step-by-step explanation:
3^-3 can be written as 1/3^3 and 3^3 = 3x3x3= 27
Therefore, the answer is 1/27.
Answer:
Probability that a car need to be repaired once = 20% = 0.20
Probability that a car need to be repaired twice = 8% = 0.08
Probability that a car need to be repaired three or more = 2% = 0.02
a) If you own two cars what is the probability that neither will need repair?
Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3
Probability that car need no repair = 1-0.3=0.7
Neither car will need repair=
b) both will need repair?
Probability both will need repair = 
c)at least one car will need repair
Neither car will need repair=
Probability that at least one car will need repair= 1-0.49 = 0.51
we just did this in math-
How to solve it:
•1. multiply 7 x 1= 7
•2. multiply 7 x 4k= 28k
so the answer is: 7+28k
i hope i have been helpful :)
I’ve attached my work...
Hope it helps!
Math-way app for problems like number 2
Have a nice day:)