Question

Quadrilateral EFGH has coordinates E(2b, 2b), F(3b, b), G(b, o), and H(0, 0). Find the midpoint of HE. Help me!

Answer 1

Answer:

$(b,b)$

Step-by-step explanation:

To get  the  result you can use the formula for the midpoint between two points, given by

$\left (\frac{x_1 + x_2}{2}, \frac{y_1+y_2}{2}\right )$

where $(x_1,y_1)$ and $(x_2,y_2)$ are the two points.

So, replace the points $(x_1,y_1)=(0,0)$ and $(x_2,y_2)=(2b,2b)$ as follows:

$\left( \frac{0+2b}{2},\frac{0+2b}{2}\right ) = \left( \frac{2b}{2},\frac{2b}{2} \right)=\left( b,b\right)$

Therfore the midpoint of HE is $(b,b)$

Answer 2

Answer:

according to the picture, it would be the 4th choice