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2 years ago

Quadrilateral EFGH has coordinates E(2b, 2b), F(3b, b), G(b, o), and H(0, 0). Find the midpoint of HE. Help me!

Mathematics

2 answers:

Vilka [71]2 years ago

8 0

Answer:

$(b,b)$

Step-by-step explanation:

To get the result you can use the formula for the midpoint between two points, given by

$\left (\frac{x_1 + x_2}{2}, \frac{y_1+y_2}{2}\right )$

where $(x_1,y_1)$ and $(x_2,y_2)$ are the two points.

So, replace the points $(x_1,y_1)=(0,0)$ and $(x_2,y_2)=(2b,2b)$ as follows:

$\left( \frac{0+2b}{2},\frac{0+2b}{2}\right ) = \left( \frac{2b}{2},\frac{2b}{2} \right)=\left( b,b\right)$

Therfore the midpoint of HE is $(b,b)$

iren2701 [21]2 years ago

4 0

Answer:

according to the picture, it would be the 4th choice

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In the figure, angle D measures 127° and angle A measures 75°.

almond37 [142]

Angles C and D are supplementary, or they add up to 180.

b = 180 - 75 - (180 - 127)

Hope this helps!

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2 years ago

Read 2 more answers

Solve the following system of equations. 2x + y = 3 x = 2y - 1 Make sure there are NO SPACES in your answer. Include a comma in

Natalka [10]

2x + y = 3
x = 2y - 1

solve for y in the first equation;
2x + y = 3
y = 3 - 2x

x = 2y - 1
x = 2(3 - 2x) - 1
x = -4x + 5

solve for x;
x = -4x + 5
x + 4x = 5
5x = 5
x = 1

solve for y;
y = 3 - 2x
y = 3 - 2(1)
y = 1

the answer is: x = 1, y = 1

hope this helps, God bless!

8 0

2 years ago

A seat on a Ferris wheel is level with the center of the wheel. The diameter of the wheel is 210 feet (ft). If the wheel

frutty [35]

Answer:

The change in the height of the seat of the Ferris wheel is a reduction in height of approximately 74.25 feet

Step-by-step explanation:

The given information are;

The position of the seat on the Ferris wheel = The center level of the wheel

The diameter of the Ferris wheel = 210 feet

The angle of rotation of the wheel = 45° counterclockwise

The height of a point on the Ferris wheel is given by the relation;

h = A·cos(b·x + c) + d

With regards to the question, we have;

h = The height of the seat of the Ferris wheel

A = The amplitude = 1/2 × The diameter of the wheel = 210/2 = 105 feet

360/b = The period

c = The phase shift = 90°

d = The mid line = 0

For a rotation of 45° counterclockwise or-45° clockwise, we have;

b·x = 45°, therefore;

h = 105 × cos(45° + 90°) + 0 = 105 × cos(135°) + 0

h = 105 × cos(135°) ≈ -74.25 feet

Therefore, the height of the seat of the Ferris wheel reduces by 74.246 feet.

6 0

2 years ago

Is 300 cm or 30 meters larger

notka56 [123]

I think it's 30 meters
I hope it helps

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3 years ago

Find the dimensions of the rectangle with area 256 square inches that has minimum perimeter, and then find the minimum perimeter

mezya [45]

Answer:

Dimensions: $A=a\cdot b=256$

Perimiter: $P=2a+2b$

Minimum perimeter: [16,16]

Step-by-step explanation:

This is a problem of optimization with constraints.

We can define the rectangle with two sides of size "a" and two sides of size "b".

The area of the rectangle can be defined then as:

$A=a\cdot b=256$

This is the constraint.

To simplify and as we have only one constraint and two variables, we can express a in function of b as:

$b=\frac{256}{a}$

The function we want to optimize is the diameter.

We can express the diameter as:

$P=2a+2b=2a+2*\frac{256}{a}$

To optimize we can derive the function and equal to zero.

$dP/da=2+2\cdot (-1)\cdot\frac{256}{a^2}=0\\\\\frac{512}{a^2}=2\\\\a=\sqrt{512/2}= \sqrt {256} =16\\\\b=256/a=256/16=16$

The minimum perimiter happens when both sides are of size 16 (a square).

4 0

2 years ago