A) cos(2x- pi/3)= 1/ căn 3

HELP ME PLS?? 2 divided by 1/2= ??

Gennadij [26K]

The answer is 4
Because 0.5 times 4 is 2

5 0

3 years ago

Read 2 more answers

Find the vertex and focus of the parabola. y2 – 4y + 12x – 8 = 0

IceJOKER [234]

Answer:

1,2

-2 2

Step-by-step explanation:

6 0

3 years ago

The value of the digit 4 in the number 42,780 is 10 times the value of the digit in which number

belka [17]

The number 4,278 I think.

Hope this helps!

7 0

3 years ago

Of the 25 girls on the Alden Middle School soccer team, 40% also play on a travel team. How many of the girls on the middle scho

SpyIntel [72]

Answer:

10 Girls

Step-by-step explanation:

Total number of girls in Alden Middle school= 25 girls

Percent of girls play for travel team= 40%

We have to find the numbers of girls who play for middle school team

Numbers of girls who play for middle school team= 25 × $\frac{40}{100}$

Numbers of girls who play for middle school team=25 × $\frac{40}{100}$

Numbers of girls who play for middle school team=10

Hence the number of girls play for travel team= 10 girls.

Hence, the correct answer is 10.

5 0

3 years ago

Calculate the length of sides triangle pqr and determine weather or not triangle is a right angled. P(-4,6) q(6,1) r(2,9)

Tom [10]

$\bold{\huge{\underline{ Solution }}}$

<h3>Given :-</h3>

We have given the coordinates of the triangle PQR that is P(-4,6) , Q(6,1) and R(2,9)

We have to calculate the length of the sides of given triangle and also we have to determine whether it is right angled triangle or not

<h3>Let's Begin :-</h3>

Here, we have 

Coordinates of P =( x1 = -4 , y1 = 6)
Coordinates of Q = ( x2 = 6 , y2 = 1 )
Coordinates of R = ( x3 = 2 , y3 = 9 )

By using distance formula 

$\pink{\bigstar}\boxed{\sf{Distance=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}$

Subsitute the required values in the above formula :-

Length of side PQ

$\sf{ = }{\sf\sqrt{ (6 - (-4))^{2} + (1 - 6)^{2}}}$

$\sf{ = }{\sf\sqrt{ (6 + 4 )^{2} + (- 5)^{2}}}$

$\sf{ = }{\sf\sqrt{ (10)^{2} + (- 5)^{2}}}$

$\sf{ = }{\sf\sqrt{ 100 + 25 }}$

$\sf{ = }{\sf\sqrt{ 125 }}$

$\sf{ = 5 }{\sf\sqrt{ 5 }}$

Length of QR

$\sf{ = }{\sf\sqrt{(2 - 6)^{2} + (9 - 1)^{2}}}$

$\sf{ = }{\sf\sqrt{(- 4 )^{2} + (8)^{2}}}$

$\sf{ = }{\sf\sqrt{16 + 64 }}$

$\sf{ = }{\sf\sqrt{80 }}$

$\sf{ = 4 }{\sf\sqrt{5 }}$

Length of RP

$\sf{ = }{\sf\sqrt{ (-4 - 2 )^{2} + (6 - 9)^{2}}}$

$\sf{ = }{\sf\sqrt{ (-6 )^{2} + (-3)^{2}}}$

$\sf{ = }{\sf\sqrt{ 36 + 9 }}$

$\sf{ = }{\sf\sqrt{ 45 }}$

$\sf{ = 3}{\sf\sqrt{ 5 }}$

We have to determine whether the triangle PQR is right angled triangle

<h3>Therefore, </h3>

By using Pythagoras theorem :-

Pythagoras theorem states that the sum of squares of two sides that is sum of squares of 2 smaller sides of triangle is equal to the square of hypotenuse that is square of longest side of triangle

That is,

$\bold{ PQ^{2} + QR^{2} = PR^{2}}$

Subsitute the required values,

$\bold{ 125 + 80 = 45 }$

$\bold{ 205 = 45 }$

From above we can conclude that,

The triangle PQR is not a right angled triangle because 205 ≠ 45 .

6 0

3 years ago