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Mariulka [41]
3 years ago
13

Let h(x)=505.5+8e−0.9x . What is h(5) ? rounded to the nearest tenth. any help would be great

Mathematics
2 answers:
madreJ [45]3 years ago
5 0

Answer:

8.9

Step-by-step explanation:

Naddik [55]3 years ago
3 0
For this case, the first thing we are going to do is rewrite the function.
 We have then:
 h (x) = 505.5 + 8 * exp (-0.9 * x)
 We evaluate the value of x = 5 in the function.
 We have then:
 h (5) = 505.5 + 8 * exp (-0.9 * 5)
 h (5) = 505.588872
 round to the nearest tenth:
 h (5) = 505.6
 Answer:
 
the value of h (5) is:
 
h (5) = 505.6
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