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3 years ago

Please help me with math please

Mathematics

2 answers:

ella [17]3 years ago

7 0

Answer is:

£62.50 (B)

SVEN [57.7K]3 years ago

6 0

Answer:

62.50

Step-by-step explanation:

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TOY has coordinates T (-3, 4), O (-4, 1) and Y (-2, 3). a translation maps point T to T' (-1, 1). find the coordinates of O' and

NeX [460]

Answer:

Answer: The correct option is (A) O' (−2, −2); Y' (0, 0).

Step-by-step explanation: Given that the co-ordinates of the vertices of ΔTOY are T(−3, 4), O (−4, 1), and Y (−2, 3). A translation maps point T to T' (−1, 1).

We are to find the co-ordinates of the points O' and Y'.

The given transformation from T to T' is

T(−3, 4) ⇒ T' (−1, 1).

Let, (−3 + x, 4 + y) = (-1, 1).

So,

and

That is, the transformation rule is

(a, b) ⇒ (a+2, b-3).

Therefore,

co-ordinates of O' are (-4+2, 1-3) = (-2, -2),

and

co-ordinates of Y' are (-2+2, 3-3) = (0, 0).

Thus, the required co-ordinates of O' and Y' are (-2, -2) and (0, 0) respectively.

Option (A) is correct.

8 0

3 years ago

Maria receivesa commission of 11.5%for each pair of shoes she sells.She earned $207 in commission last week.What was the dollar

Kamila [148]

Answer:

$1800

Step-by-step explanation:

You would use proportions. 11.5/100 (11.5%) multiplied by 207/x.

Cross multiply 100 and 207, then divide that answer by 11.5. You should get 1,800 as your answer.

Therefore, the dollar amount of shoes that Maria sold is $1800.

5 0

3 years ago

How to solve for x in the equation 3x=28-y?

Veronika [31]

Answer:

x=(28-y)/3

Step-by-step explanation:

Just divide both sides by 3.

6 0

3 years ago

a biker must circle a 12 mile track twice. His average speed must be 60mph. On his first lap he averaged 50 mph. How fast must h

liq [111]

Answer:

75 mph

Step-by-step explanation:

A biker must circle a 12-mile track twice. His average speed must be 60 mph.

So, the average time required to cover the distance is $\frac{2 \times 12}{60} = 0.4$ hours.

Now, on his first lap, he averaged 50 mph.

So, he covered this 12 miles track in $\frac{12}{50} = 0.24$ hours.

Hence, he has to cover the next 12 miles track in (0.4 - 0.24) = 0.16 hours.

Therefore, his average speed in the second round must be $\frac{12}{0.16} = 75$ mph to qualify. (Answer)

8 0

3 years ago

Show all steps please

OLga [1]

$9-8x\geq0\ \ \ |subtract\ 9\ from\ both\ sides\\\\-8x\geq-9\ \ \ \ |change\ signs\\\\8x\leq9\ \ \ \ |divide\ both\ sides\ by\ 8\\\\x\leq9\\\\ |9-8x|=\left\{\begin{array}{ccc}9-8x&for\ x\leq9\\8x-9&for\ x \ \textgreater \ 9\end{array}\right$

$1^o\ x\in(-\infty;\ 9]\to|9-8x|=9-8x\\\\9(9-8x)=2x+3\\81-72x=2x+3\ \ \ \ |subtract\ 81\ from\ both\ sides\\-72x=2x-78\ \ \ \ |subtract\ 2x\ from\ both\ sides\\-74x=-78\ \ \ \ |divide\ both\ sides\ by\ (-74)\\\\x=\dfrac{-78:2}{-74:2}\\\\\boxed{x=\frac{39}{37}}\in(-\infty;\ 9]$

$2^o\ x\in(9;\ \infty)\to|9-8x|=8x-9\\\\9(8x-9)=2x+3\\72x-81=2x+3\ \ \ \ |add\ 81\ to\ both\ sides\\72x=2x+84\ \ \ \ |subtract\ 2x\ from\ both\ sides\\70x=84\ \ \ \ \ \ |divide\ both\ sides\ by\ 70\\\\x=\dfrac{84:14}{70:14}\\\\x=\dfrac{6}{5}\notin(9;\ \infty)\\\\\\Answer:\boxed{x=\frac{39}{37}}$

6 0

3 years ago