In order to find the answer to this question you will have to divide 24 and 6.
Therefore the paper airplane flies "4 meters every second."
Hope this helps.
<span>4x•2-12x=7
Subtract 12x from 4x
-8x*2=7
Divide 2 on both sides
-8x=3.5
Divide both sides by -8
Final Answer: x= -0.4375</span>
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Answer:
The distance from AD to BC is 7
Step-by-step explanation:
The information given are;
The type of inscribed quadrilateral ABCD = Isosceles trapezoid
The radius of the circle = 5
Segment AD of ABCD = 6
The median of the trapezoid ABCD = 7
Given the trapezoid theorem, the median is equal to half the length of the two bases added together, we have;
(AD + BC)/2 = 7
Which gives;
(6 + BC)/2 = 7
BC = 7×2 - 6 = 8
Therefore the distance from AD to BC is given by the distance from BC to the median line added to the distance from AD to the median line given as follows;
The distance from BC to the median = √(Radius² - (BC/2)²) = √(5² - (8/2)²) = 3
The distance from BC to the median = 3
The distance from AD to the median = √(Radius² - (AD/2)²) = √(5² - (6/2)²) = 4
Which gives;
The distance from AD to BC = 3 + 4 = 7
Answer:
The error bound is of 13.5 corn kernels.
Step-by-step explanation:
Any confidence interval has a lower bound and an upper bound. The error bound is the difference between the values of those two bounds, divided by 2.
In this problem, we have that:
Lower bound: 858.50
Upper bound: 885.50
Error bound: (885.50-858.50)/2 = 13.5
The error bound is of 13.5 corn kernels.
