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nata0808 [166]
3 years ago
12

Given that tan θ= -65/72 and that angle θ terminates in quadrant II, then what is the value of cos θ?

Mathematics
1 answer:
adoni [48]3 years ago
7 0

Answer:

cosθ = -\frac{72}{97}

Step-by-step explanation:

tanθ = -(65/72)

If it is in the 2nd quadrant, this means that y is positive but x is negative

tanθ= opposite/adjacent or (y/x)

tanθ=\frac{65}{-72}

We know that the adjacent value = -72 and the opposite value = 65

The hypotenuse can be get by the following

\sqrt{(65)^2+(-72)^2}  = 97

cosθ is just adjacent/hypotenuse

Our adjacent value is -72

Our hypotenuse is 97, therefore

cosθ = -\frac{72}{97}

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